Chapter 10: Problem 98
Look Alikes . . . a. \(a^{2}+a-7=0\) b. \(a^{2}-a-7=0\)
Short Answer
Expert verified
The solutions for (a) are \( \frac{-1 \pm \sqrt{29}}{2} \) and for (b) are \( \frac{1 \pm \sqrt{29}}{2} \).
Step by step solution
01
Identify the Quadratic Formula
The quadratic formula is used to find the roots of a quadratic equation of the form \(ax^2 + bx + c = 0\). The formula is: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
02
Apply the Formula to Part (a)
In the equation \(a^2 + a - 7 = 0\), identify that \(a = 1\), \(b = 1\), and \(c = -7\). Substitute these into the quadratic formula: \(a = \frac{-1 \pm \sqrt{1^2 - 4 \cdot 1 \cdot (-7)}}{2 \cdot 1}\).
03
Solve the Discriminant for Part (a)
Calculate the value inside the square root, known as the discriminant: \(1^2 - 4 \cdot 1 \cdot (-7) = 1 + 28 = 29\).
04
Calculate the Roots for Part (a)
Substitute the discriminant back into the formula: \(a = \frac{-1 \pm \sqrt{29}}{2}\). This results in two solutions: \(a = \frac{-1 + \sqrt{29}}{2}\) and \(a = \frac{-1 - \sqrt{29}}{2}\).
05
Apply the Formula to Part (b)
In the equation \(a^2 - a - 7 = 0\), identify \(a = 1\), \(b = -1\), and \(c = -7\). Substitute these into the quadratic formula: \(a = \frac{-(-1) \pm \sqrt{(-1)^2 - 4 \cdot 1 \cdot (-7)}}{2 \cdot 1}\).
06
Solve the Discriminant for Part (b)
Calculate the discriminant for this equation: \((-1)^2 - 4 \cdot 1 \cdot (-7) = 1 + 28 = 29\).
07
Calculate the Roots for Part (b)
Substitute the discriminant back into the formula: \(a = \frac{1 \pm \sqrt{29}}{2}\). This results in two solutions: \(a = \frac{1 + \sqrt{29}}{2}\) and \(a = \frac{1 - \sqrt{29}}{2}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Quadratic Formula
The quadratic formula is a powerful tool designed specifically to solve any quadratic equation, which takes the general form \( ax^2 + bx + c = 0 \). Whether you're dealing with a simple or complex quadratic, this formula allows you to find the exact solutions, or roots, for the equation. The formula is expressed as:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
The Role of the Discriminant
The discriminant is an integral part of the quadratic formula. It is the component under the square root sign, expressed as \( b^2 - 4ac \). Calculating the discriminant is essential because it indicates the nature of the roots:
- If the discriminant is positive, you will have two distinct real roots.
- If it equals zero, there is exactly one real root, also known as a repeated or double root.
- If the discriminant is negative, the roots are not real numbers but complex or imaginary roots.
- Equation: \( a^2 + a - 7 = 0 \) gives \( b^2 - 4ac = 29 \)
- Equation: \( a^2 - a - 7 = 0 \) also gives \( b^2 - 4ac = 29 \)
Finding the Roots of Equations
The roots of a quadratic equation are the solutions for the variable that make the equation equal to zero. Once the discriminant is calculated and found to be non-negative, finding the roots becomes straightforward. With a positive discriminant, apply the quadratic formula:
- For \( a^2 + a - 7 = 0 \), the roots are: \( a = \frac{-1 + \sqrt{29}}{2} \) and \( a = \frac{-1 - \sqrt{29}}{2} \)
- For \( a^2 - a - 7 = 0 \), the roots are: \( a = \frac{1 + \sqrt{29}}{2} \) and \( a = \frac{1 - \sqrt{29}}{2} \)