Chapter 10: Problem 60
Solve each equation. $$ \left(a^{2}-4\right)^{2}-4\left(a^{2}-4\right)-32=0 $$
Short Answer
Expert verified
The solutions are \( a = 0, \pm 2\sqrt{3} \).
Step by step solution
01
Substitute for simplification
Let \( u = a^2 - 4 \). This substitution simplifies the equation to \( u^2 - 4u - 32 = 0 \).
02
Identify equation type
The equation is a quadratic equation in the form \( u^2 - 4u - 32 = 0 \), which can be solved using the quadratic formula.
03
Apply the quadratic formula
Use the quadratic formula \( u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) where \( a = 1 \), \( b = -4 \), and \( c = -32 \).
04
Calculate the discriminant
The discriminant \( b^2 - 4ac = (-4)^2 - 4(1)(-32) = 16 + 128 = 144 \).
05
Solve for u
Using the quadratic formula: \( u = \frac{-(-4) \pm \sqrt{144}}{2(1)} \). This simplifies to \( u = \frac{4 \pm 12}{2} \).
06
Calculate each solution for u
The two solutions for \( u \) are \( u = \frac{16}{2} = 8 \) and \( u = \frac{-8}{2} = -4 \).
07
Solve for a
Recall that \( u = a^2 - 4 \). Substitute back to find \( a \). For \( u = 8 \), \( a^2 - 4 = 8 \) implies \( a^2 = 12 \). Thus, \( a = \pm \sqrt{12} = \pm 2\sqrt{3} \). For \( u = -4 \), \( a^2 - 4 = -4 \) implies \( a^2 = 0 \), so \( a = 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful technique to simplify complex equations by replacing intricate expressions with a single variable. In this context, the equation \( (a^2 - 4)^2 - 4(a^2 - 4) - 32 = 0 \) is quite complex due to the quadratic form nested within it. To solve such an equation, we first make a smart substitution that makes the problem easier to manage. For our example, let \( u = a^2 - 4 \). By doing this, our original equation transforms into a simpler quadratic form: \( u^2 - 4u - 32 = 0 \).This transformation helps in two significant ways:
- It reduces the equation's complexity by replacing intricate terms with a single variable \( u \).
- It allows us to then apply direct methods suitable for quadratic equations to find possible values for \( u \).
Quadratic Formula
The quadratic formula is a universal solution method for quadratic equations of the form \( ax^2 + bx + c = 0 \). This formula is especially useful when factoring is difficult or impossible. The general form of the quadratic formula is:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]In our example, after substitution, we obtained the quadratic equation \( u^2 - 4u - 32 = 0 \), where \( a = 1 \), \( b = -4 \), and \( c = -32 \). By plugging these values into the formula, we directly solve for \( u \):
- Calculate the discriminant \( b^2 - 4ac \) before solving. This step checks for real solutions.
- Substitute \( a \), \( b \), and \( c \) into the quadratic formula.
- Solve to find the two potential solutions for \( u \).
Discriminant Calculation
The discriminant is a key part of the quadratic formula, represented by \( b^2 - 4ac \). It gives valuable insight into the nature of the roots of a quadratic equation.In our example where \( u^2 - 4u - 32 = 0 \), let's calculate:\[ (-4)^2 - 4 \times 1 \times (-32) = 16 + 128 = 144 \]This positive discriminant \( 144 \) indicates that the quadratic equation has two distinct real roots. Here's why calculating the discriminant is useful:
- A positive discriminant means two unique real solutions.
- A discriminant of zero means one real solution (a double root).
- A negative discriminant means two complex conjugate solutions (no real solutions).