Chapter 6: Problem 65
Factor completely. Remember to look first for a common factor. If a polynomial is prime, state this. $$ \frac{1}{49}-x^{2} $$
Short Answer
Expert verified
(\(\frac{1}{7} + x\))(\(\frac{1}{7} - x\))
Step by step solution
01
Identify a common factor
Observe the given expression: \(\frac{1}{49} - x^2\). Look for any common factors in the terms. In this case, there are no common factors between \(\frac{1}{49}\) and \(-x^2\).
02
Recognize the form of the polynomial
Notice that the expression is in the form of a difference of squares. A difference of squares has the form \(a^2 - b^2\), which can be factored into \((a + b)(a - b)\).
03
Rewrite terms as squares
Rewrite \(\frac{1}{49}\) as a square. Since \(\frac{1}{49} = \frac{1^2}{7^2} = (\frac{1}{7})^2\), the expression can be rewritten as \((\frac{1}{7})^2 - x^2\).
04
Apply the difference of squares formula
Using the difference of squares formula \((a^2 - b^2 = (a + b)(a - b))\), let \(a = \frac{1}{7}\) and \(b = x\). The expression becomes: \[(\frac{1}{7})^2 - x^2 = (\frac{1}{7} + x)(\frac{1}{7} - x)\].
05
Write the final factored form
The completely factored form of the polynomial is \((\frac{1}{7} + x)(\frac{1}{7} - x)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference of Squares
The concept of the **difference of squares** is a powerful tool in factoring polynomials. It applies to expressions where two squared terms are subtracted from each other. A standard difference of squares takes the form \(a^2 - b^2\), and it can be factored into \((a + b)(a - b)\).
For example, if we have an expression like \(x^2 - 9\), we can rewrite this as \(x^2 - 3^2\). Using the difference of squares formula, we factor this into \((x + 3)(x - 3)\).
In your exercise, \(\frac{1}{49} - x^2\), notice how it's converted to the form \((\frac{1}{7})^2 - x^2\). Which then allows us to apply the difference of squares formula, resulting in the factors \(\frac{1}{7} + x\) and \(\frac{1}{7} - x\).
For example, if we have an expression like \(x^2 - 9\), we can rewrite this as \(x^2 - 3^2\). Using the difference of squares formula, we factor this into \((x + 3)(x - 3)\).
In your exercise, \(\frac{1}{49} - x^2\), notice how it's converted to the form \((\frac{1}{7})^2 - x^2\). Which then allows us to apply the difference of squares formula, resulting in the factors \(\frac{1}{7} + x\) and \(\frac{1}{7} - x\).
Factoring Techniques
Factoring polynomials can be approached using various techniques. Here are some of the most common methods:
- **Common Factor Technique**: First, always check if there's a common factor in all terms of the polynomial. If found, factor it out.
- **Difference of Squares**: As discussed, expressions like \(a^2 - b^2\) can be factored into \((a + b)(a - b)\).
- **Trinomials**: For expressions like \(ax^2 + bx + c\), where \(a, b,\) and \(c\) are constants, specific factoring methods apply, such as finding two numbers that multiply to \(ac\) and add to \(b\).
- **Special Products**: Recognize patterns such as cubes of sums and differences, which have their own specific factoring formulas.
Polynomials
Understanding **polynomials** is key to mastering algebra. A polynomial is a mathematical expression consisting of variables, coefficients, and non-negative integer exponents. For example, \(3x^2 + 2x - 5\) is a polynomial with three terms.
Here are some important features of polynomials:
Your exercise involves the polynomial \(\frac{1}{49} - x^2\). Although it only has two terms, it is still considered a polynomial. The degree is 2, and the coefficients are \(\frac{1}{49}\) and -1. Understanding these basics helps in identifying how to factor different types of polynomials.
Here are some important features of polynomials:
- **Terms**: Parts of the polynomial separated by + or - signs.
- **Degree**: The highest exponent in the polynomial. For \(3x^2 + 2x - 5\), the degree is 2.
- **Coefficients**: Numbers multiplying the variables. In \(3x^2 + 2x - 5\), the coefficients are 3, 2, and -5.
- **Constants**: Terms without variables, e.g., -5 in \(3x^2 + 2x - 5\).
Your exercise involves the polynomial \(\frac{1}{49} - x^2\). Although it only has two terms, it is still considered a polynomial. The degree is 2, and the coefficients are \(\frac{1}{49}\) and -1. Understanding these basics helps in identifying how to factor different types of polynomials.