Chapter 6: Problem 47
Solve. $$ x^{3}+1=0 $$
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Chapter 6: Problem 47
Solve. $$ x^{3}+1=0 $$
These are the key concepts you need to understand to accurately answer the question.
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Solve. Round any irrational solutions to the nearest thousandth. \( 8 x^{3}+1=4 x^{2}+2 x \)
Factor completely. Remember to look first for a common factor. If a polynomial is prime, state this. $$ p^{2} q-25 q+3 p^{2}-75 $$
Review multiplying binomials using FOIL $$ (a-1)(a-3) $$
Solve. Round any irrational solutions to the nearest thousandth. $$ 2 x^{2}+8 x+1=0 $$
Akio concludes that since \(x^{2}-9=(x-3)(x+3)\) it must follow that \(x^{2}+9=(x+3)(x-3) .\) What mistake(s) is he making?
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