Chapter 13: Problem 8
Match the conic section with the equation in the column on the right that represents that type of conic section. _____ A parabola opening to the right or to the left a) \(\frac{x^{2}}{10}+\frac{y^{2}}{12}=1\) b) \((x+1)^{2}+(y-3)^{2}=30\) c) \(y-x^{2}=5\) d) \(\frac{x^{2}}{9}-\frac{y^{2}}{10}=1\) e) \(x-2 y^{2}=3\) f) \(\frac{y^{2}}{20}-\frac{x^{2}}{35}=1\) g) \(3 x^{2}+3 y^{2}=75\) h) \(\frac{(x-1)^{2}}{10}+\frac{(y-4)^{2}}{8}=1\)
Short Answer
Step by step solution
Identify the Conic Sections
Compare Each Equation
Equation a
Equation b
Equation c
Equation d
Equation e
Equation f
Equation g
Equation h
Match the Parabola Opening to the Right or to the Left
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
parabola
In the given exercise, we can see an example in Equation c: \( y - x^2 = 5 \), which can be rearranged to \( y = x^2 + 5 \), showing a parabola opening upwards. Also, Equation e: \( x - 2y^2 = 3 \) can be rewritten as \( x = 2y^2 + 3 \), indicating a parabola opening to the right.
ellipse
In the exercise, Equation a: \( \frac{x^2}{10} + \frac{y^2}{12} = 1 \) matches the form of an ellipse. Similarly, Equation h: \( \frac{(x-1)^2}{10} + \frac{(y-4)^2}{8} = 1 \) is a translated ellipse centered at (1, 4).
hyperbola
In the exercise, Equation d: \( \frac{x^2}{9} - \frac{y^2}{10} = 1 \) is a hyperbola. Equation f: \( \frac{y^2}{20} - \frac{x^2}{35} = 1 \) is also in the standard hyperbola form but oriented differently.
circle
In the exercise, Equation b: \( (x + 1)^2 + (y - 3)^2 = 30 \) represents a circle with a radius of \( \sqrt{30} \), centered at (-1, 3). Equation g: \( 3x^2 + 3y^2 = 75 \) can be simplified by dividing by 3 to get \( x^2 + y^2 = 25 \), indicating a circle with a radius of 5.