Chapter 12: Problem 57
Solve by completing the square. $$ x^{2}+8 x=1 $$
Short Answer
Expert verified
x = -4 + \sqrt{17} and x = -4 - \sqrt{17}
Step by step solution
01
Move the constant term to the other side
Start by isolating the quadratic and linear terms on one side of the equation. Subtract 1 from both sides of the equation: \[ x^{2} + 8x - 1 = 0 \]
02
Add the term to complete the square
To complete the square, take half of the coefficient of x, which is 8, then square it: \[ \left(\frac{8}{2}\right)^2 = 4^2 = 16 \]Now add this value to both sides of the equation: \[ x^{2} + 8x + 16 = 1 + 16 \]
03
Write the left side as a squared binomial
The left side of the equation is now a perfect square trinomial. Write it as follows: \[ (x + 4)^2 = 17 \]
04
Take the square root of both sides
Next, take the square root of both sides of the equation to solve for x: \[ \sqrt{(x + 4)^2} = \pm \sqrt{17} \]This simplifies to: \[ x + 4 = \pm \sqrt{17} \]
05
Solve for x
Finally, solve for x by subtracting 4 from both sides: \[ x = -4 \pm \sqrt{17} \]So the solutions are: \[ x = -4 + \sqrt{17} \text{ and } x = -4 - \sqrt{17} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a type of polynomial equation of degree 2. The standard form of a quadratic equation is \(ax^2 + bx + c = 0\). Here, 'a', 'b', and 'c' are constants, and 'x' represents the variable. For example, in the equation \(x^2 + 8x - 1 = 0\), 'a' is 1, 'b' is 8, and 'c' is -1.
Quadratic equations are fundamental in algebra and have various methods for finding their solutions, such as:
When solving by completing the square, we aim to form a perfect square trinomial on one side of the equation.
Quadratic equations are fundamental in algebra and have various methods for finding their solutions, such as:
- Factoring
- Using the quadratic formula: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
- Completing the square.
When solving by completing the square, we aim to form a perfect square trinomial on one side of the equation.
Perfect Square Trinomial
A perfect square trinomial is a quadratic expression of the form \((x + p)^2\), which expands to \(x^2 + 2px + p^2\). To solve by completing the square, we create this form from an existing equation.
In the given problem, \(x^2 + 8x + 16 = 17\) is transformed into \((x + 4)^2 = 17\). Here’s how it’s done:
In the given problem, \(x^2 + 8x + 16 = 17\) is transformed into \((x + 4)^2 = 17\). Here’s how it’s done:
- Identify the coefficient of the 'x' term (8 in this case).
- Take half of this coefficient: \(\frac{8}{2} = 4\).
- Square this result: \(4^2 = 16\).
Adding 16 to both sides of the equation transforms it into a perfect square trinomial on the left side, which can then be written as \((x + 4)^2\). Recognizing and creating perfect square trinomials is crucial for solving quadratic equations by completing the square.
Square Root
The square root of a number is a value that, when multiplied by itself, gives the original number. For example, the square root of 16 is 4, since \(4 \times 4 = 16\). In solving equations using square roots, we utilize both the positive and negative roots.
With the equation \((x + 4)^2 = 17\), we take the square root of both sides to solve for 'x'. This simplifies to: \(\sqrt{(x + 4)^2} = \pm \sqrt{17}\)
This means: \(x + 4 = \sqrt{17}\) or \(x + 4 = -\sqrt{17}\). These steps yield the two solutions:
Always remember to consider both positive and negative roots when solving quadratic equations using square roots. This ensures you find all possible solutions.
With the equation \((x + 4)^2 = 17\), we take the square root of both sides to solve for 'x'. This simplifies to: \(\sqrt{(x + 4)^2} = \pm \sqrt{17}\)
This means: \(x + 4 = \sqrt{17}\) or \(x + 4 = -\sqrt{17}\). These steps yield the two solutions:
- \(x = -4 + \sqrt{17}\)
- \(x = -4 - \sqrt{17}\)
Always remember to consider both positive and negative roots when solving quadratic equations using square roots. This ensures you find all possible solutions.