Chapter 11: Problem 59
Solve by completing the square. Show your work. $$ t^{2}-10 t=-23 $$
Short Answer
Expert verified
\[ t = 5 \pm 4\sqrt{3} \]
Step by step solution
01
Move the constant to the other side
Start by adding 23 to both sides of the equation to move the constant to the right side.\[ t^2 - 10t + 0 = -23 + 23 \]This simplifies to:\[ t^2 - 10t = 23 \]
02
Identify the coefficient of the linear term
The coefficient of the linear term is -10. The goal is to complete the square, so identify \(b\) in the term \(t^2 + bt\). Here, \(b = -10\).
03
Find the value to complete the square
To complete the square, take half of the coefficient of \(t\), then square it. Half of -10 is -5, and \((-5)^2 = 25\).
04
Add and subtract the squared value inside the equation
Add and subtract the squared value (25) inside the equation:\[ t^2 - 10t + 25 - 25 = 23 \]Which simplifies to:\[ t^2 - 10t + 25 = 48 \]
05
Write the left side as a square
The left-hand side is now a perfect square trinomial:\[ (t - 5)^2 = 48 \]
06
Solve for t by taking the square root
Take the square root of both sides of the equation. Remember to consider both the positive and negative square roots:\[ t - 5 = \pm \sqrt{48} \]Which simplifies to:\[ t - 5 = \pm 4\sqrt{3} \]
07
Solve for t
Isolate \(t\) by adding 5 to both sides. This gives the final solution:\[ t = 5 \pm 4\sqrt{3} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are a type of polynomial equation of the second degree. They have the general form: \[ ax^2 + bx + c = 0 \] Here, *a*, *b*, and *c* are constants with *a* ≠0. Quadratic equations are characterized by the highest exponent of the variable being 2. Some common methods to solve quadratic equations include:
- Factoring
- Using the quadratic formula
- Completing the square
Solving Quadratics
Let's discuss how to solve quadratic equations by completing the square, using the given example \[ t^2 - 10t = -23 \]. Here's how it works:First, we move the constant term to the other side of the equation. \[ t^2 - 10t + 23 = 0 \] Next, focus on the linear term. The coefficient of *t* is -10. Take half of this coefficient, square it, and add and subtract this value within the equation.
- Half of -10 is -5.
- Square -5 to get 25.
Algebraic Techniques
Algebraic techniques are fundamental tools used to manipulate and solve equations. These include:
- Rearranging equations
- Combining like terms
- Using distributive property
- Factoring
- Expanding
- Adding or subtracting the same quantity to both sides of the equation (rearranging equations)
- Identifying and manipulating coefficients
- Using the property \[(a - b)^2 = a^2 - 2ab + b^2\] to form a perfect square trinomial
- Factoring the trinomial into a binomial square
- Solving the resulting simplified balanced equation