Chapter 11: Problem 45
Write a quadratic equation having the given numbers as solutions. $$ 4 i,-4 i $$
Short Answer
Expert verified
The quadratic equation is x^2 + 16 = 0.
Step by step solution
01
Understand Conjugate Solutions
In a quadratic equation, if one of the solutions is a complex number, then its conjugate is also a solution. In this problem, the solutions given are complex conjugates: 4i and -4i.
02
Write the Solution Form
If the solutions are provided, the quadratic equation can be written in the form (x - r1)(x - r2) = 0, where r1 and r2 are the roots. For this problem, r1 = 4i and r2 = -4i.
03
Substitute Values and Expand
Substitute the given solutions into the equation form from Step 2: (x - 4i)(x + 4i) = 0. Expand this product:(x - 4i)(x + 4i) = x^2 - (4i)^2. Recall the property of complex numbers: (i)^2 = -1, so (4i)^2 = 16(-1) = -16.
04
Simplify the Equation
Now the equation becomes x^2 - (-16) = 0, which simplifies to x^2 + 16 = 0.
05
Write the Final Equation
The final quadratic equation with the given solutions 4i and -4i is x^2 + 16 = 0.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are a type of polynomial equation of the form \(ax^2 + bx + c = 0\). The highest exponent of the variable (usually x) is 2 in a quadratic equation. Here, 'a', 'b', and 'c' are constants where 'a' is non-zero.
Quadratic equations can have different types of solutions:
Quadratic equations can have different types of solutions:
- Two distinct real roots
- One real root
- Two complex roots
Complex Numbers
Complex numbers expand our understanding of numbers by adding a dimension beyond the real number line. They are of the form \(a + bi\) where 'a' and 'b' are real numbers and 'i' is the imaginary unit defined by \(i^2 = -1\). This allows us to solve equations that don't have real solutions.
For example, the equation \(x^2 + 1 = 0\) has no real solutions. However, if we use complex numbers, the solutions are \(i\) and \(-i\). Complex numbers are often used in engineering, physics, and applied mathematics.
To add or subtract complex numbers, combine their real parts and imaginary parts separately:
\((a + bi)(c + di) = ac + adi + bci + bdi^2 = (ac - bd) + (ad + bc)i\)
For example, the equation \(x^2 + 1 = 0\) has no real solutions. However, if we use complex numbers, the solutions are \(i\) and \(-i\). Complex numbers are often used in engineering, physics, and applied mathematics.
To add or subtract complex numbers, combine their real parts and imaginary parts separately:
- Adding: \((a + bi) + (c + di) = (a+c) + (b+d)i\)
- Subtracting: \((a + bi) - (c + di) = (a-c) + (b-d)i\)
\((a + bi)(c + di) = ac + adi + bci + bdi^2 = (ac - bd) + (ad + bc)i\)
Conjugate Roots
In quadratic equations, when dealing with complex roots, they occur as conjugate pairs. The complex conjugate of \(a + bi\) is \(a - bi\). This property ensures that the coefficients of the equation remain real.
For example, if \(4i\) is a root of a quadratic equation, \(-4i\) must also be a root. Complex conjugates have the same real part but opposite imaginary parts.
When forming quadratic equations from given roots, such as \(4i\) and \(-4i\), we use the factored form \((x - r1)(x - r2) = 0\). This simplifies to:
For example, if \(4i\) is a root of a quadratic equation, \(-4i\) must also be a root. Complex conjugates have the same real part but opposite imaginary parts.
When forming quadratic equations from given roots, such as \(4i\) and \(-4i\), we use the factored form \((x - r1)(x - r2) = 0\). This simplifies to:
- \((x - 4i)(x + 4i) = 0\)
- \(x^2 - (4i)^2 = x^2 - (16)(-1) = x^2 + 16\)