Chapter 11: Problem 24
Solve. $$ x^{2}+11=6 x $$
Short Answer
Expert verified
The solutions are complex: $$x = 3 + i\sqrt{2}$$ and $$x = 3 - i\sqrt{2}$$.
Step by step solution
01
Write the Equation in Standard Form
First, rearrange the given equation to match the standard form of a quadratic equation, which is $$ax^2 + bx + c = 0$$. The given equation is $$x^2 + 11 = 6x$$. Subtract 6x from both sides to rearrange the equation: $$ x^2 - 6x + 11 = 0$$.
02
Identify Coefficients
Identify the coefficients of the equation $$x^2 - 6x + 11 = 0$$. Here, $$a = 1$$, $$b = -6$$, and $$c = 11$$.
03
Calculate the Discriminant
Calculate the discriminant using the formula $$\Delta = b^2 - 4ac$$. Substituting the values: $$\Delta = (-6)^2 - 4(1)(11)$$ Simplify: $$\Delta = 36 - 44$$ $$\Delta = -8$$
04
Analyze the Discriminant
Since the discriminant $$\Delta$$ is negative ( $$\Delta = -8$$), the quadratic equation has no real solutions; both solutions will be complex.
05
Find the Solutions Using the Quadratic Formula
Use the quadratic formula $$x = \frac{-b \pm \sqrt{\Delta}}{2a}$$. Substituting the values: $$x = \frac{-(-6) \pm \sqrt{-8}}{2(1)}$$ Simplify: $$x = \frac{6 \pm \sqrt{8}i}{2}$$. Further simplify to get the two complex solutions: $$x = 3 \pm i\sqrt{2}$$.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a reliable method to solve any quadratic equation. It's given by the formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
This formula provides the roots of a quadratic equation \( ax^2 + bx + c = 0 \).
Here's how to use it:
\[ x = \frac{6 \pm \sqrt{-8}}{2} \]
These roots are simplified to \[ x = 3 \pm i\sqrt{2} \].
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
This formula provides the roots of a quadratic equation \( ax^2 + bx + c = 0 \).
Here's how to use it:
- Identify the coefficients \(a\), \(b\), and \(c\) from the standard form.
- Substitute these coefficients into the quadratic formula.
- Calculate the discriminant \( \Delta \) (the part under the square root).
- Use the discriminant to find the roots.
\[ x = \frac{6 \pm \sqrt{-8}}{2} \]
These roots are simplified to \[ x = 3 \pm i\sqrt{2} \].
Complex Solutions
Quadratic equations can sometimes have complex solutions, especially when the discriminant is negative.
Complex numbers have a real part and an imaginary part and are written in the form \( a + bi \), where \( i \) is the imaginary unit. It’s defined by the property that \( i^2 = -1 \).
In our example, the discriminant is \( \Delta = -8 \), giving us complex solutions. When plugging the discriminant into the quadratic formula, we get:
\[ x = 3 \pm i\sqrt{2} \]
Here, \( 3 \) is the real part and \( \pm \sqrt{2}i \) is the imaginary part.
These solutions mean that the parabola described by the quadratic equation does not intersect the x-axis and lies entirely above or below it, depending on the sign of the leading coefficient.
Complex numbers have a real part and an imaginary part and are written in the form \( a + bi \), where \( i \) is the imaginary unit. It’s defined by the property that \( i^2 = -1 \).
In our example, the discriminant is \( \Delta = -8 \), giving us complex solutions. When plugging the discriminant into the quadratic formula, we get:
\[ x = 3 \pm i\sqrt{2} \]
Here, \( 3 \) is the real part and \( \pm \sqrt{2}i \) is the imaginary part.
These solutions mean that the parabola described by the quadratic equation does not intersect the x-axis and lies entirely above or below it, depending on the sign of the leading coefficient.
Discriminant
The discriminant \( \Delta \) of a quadratic equation \( ax^2 + bx + c = 0 \) is given by:
\[ \Delta = b^2 - 4ac \]
The value of the discriminant determines the nature of the roots of the quadratic equation:
\[ \Delta = (-6)^2 - 4(1)(11) = 36 - 44 = -8 \]
Since \( \Delta = -8 \), it's negative, indicating the quadratic equation has two complex solutions.
\[ \Delta = b^2 - 4ac \]
The value of the discriminant determines the nature of the roots of the quadratic equation:
- If \( \Delta > 0 \), the equation has two distinct real roots.
- If \( \Delta = 0 \), the equation has one real root (a repeated root).
- If \( \Delta < 0 \), the equation has two complex conjugate roots.
\[ \Delta = (-6)^2 - 4(1)(11) = 36 - 44 = -8 \]
Since \( \Delta = -8 \), it's negative, indicating the quadratic equation has two complex solutions.