Chapter 6: Problem 4
Consider \(b>0, b \neq 1 .\) Prove \(\log _{b} y=\frac{L(y)}{L(b)}\) for \(y \in(0, \infty)\)
Short Answer
Expert verified
By using the change of base formula, we can prove that \[ \text{log}_b(y) = \frac{L(y)}{L(b)} \]
Step by step solution
01
- Understanding the logarithm properties
Recall that the logarithm function is the inverse of the exponential function. The change of base formula for logarithms is given by: \[ \frac{\text{log}_a(x)}{\text{log}_a(b)} = \text{log}_b(x) \]
02
- Rewrite the given logarithm with natural log
Express the logarithm with respect to the natural logarithm (denoted as \(\text{ln}\)). Use \(\text{log}_b(y)\), so we have: \[ \text{log}_b(y) = \frac{\text{ln}(y)}{\text{ln}(b)} \]
03
- Relate to given question terms
The problem states \(\text{log}_b(y) = \frac{L(y)}{L(b)}\). Recognize that \(L(x)\) is used here as a general logarithmic function, similar to the natural logarithm. Thus \[ L(y) = \text{ln}(y) \ \text{and} \ L(b) = \text{ln}(b) \]
04
- Substitute natural logs back into the expression
Using the expressions from the previous step, substitute \(L(y)\) and \(L(b)\) into the right-hand side of the equation: \[ \text{log}_b(y) = \frac{\text{ln}(y)}{\text{ln}(b)} \] matches \[ \frac{L(y)}{L(b)}\]
05
- Conclude
Since the expressions \( \text{log}_b(y) = \frac{\text{ln}(y)}{\text{ln}(b)}\) and \( \frac{L(y)}{L(b)}\) are identical, we have shown that \[ \text{log}_b(y) = \frac{L(y)}{L(b)} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Change of Base Formula
The change of base formula is a crucial property of logarithms. It allows us to convert a logarithm to a different base using a simple formula. If you have a logarithm with base \(b\) and you want to express it in terms of another base \(a\), you can use the following formula: \(\text{log}_b(y) = \frac{\text{log}_a(y)}{\text{log}_a(b)} \).
This formula is very helpful in simplifying logarithmic expressions and in computational situations where a specific base is more convenient. For example: \(\text{log}_b(y) = \frac{\text{ln}\big(y\big)}{\text{ln}\big(b\big)} \)
Here, \( \text{ln} \) is the natural logarithm, which is a common choice due to its properties in calculus and its ease of use in calculations. Always remember that the base change formula essentially normalizes the logarithm to a common base, making complex calculations much easier.
This formula is very helpful in simplifying logarithmic expressions and in computational situations where a specific base is more convenient. For example: \(\text{log}_b(y) = \frac{\text{ln}\big(y\big)}{\text{ln}\big(b\big)} \)
Here, \( \text{ln} \) is the natural logarithm, which is a common choice due to its properties in calculus and its ease of use in calculations. Always remember that the base change formula essentially normalizes the logarithm to a common base, making complex calculations much easier.
Natural Logarithm
The natural logarithm, denoted as \( \text{ln} \), is a logarithm with base \(e \) where \( e \) is an irrational and transcendental number approximately equal to 2.71828. The natural logarithm has several important properties that make it very useful, especially in calculus and higher-level mathematics:
- The natural log of 1 is 0: \(\text{ln}(1) = 0\)
- The natural log of \(e\) is 1: \(\text{ln}(e) = 1\)
Inverse Function
An inverse function essentially undoes the work of the original function. For a function \(f(x)\), its inverse, usually denoted as \(f^{-1}(x)\), satisfies the condition: \( f(f^{-1}(x)) = x \) and \( f^{-1}(f(x)) = x \).
When we talk about logarithms and exponential functions, they are a classical example of inverse functions. The exponential function \( \text{e}^x \) is the inverse of the natural logarithm \( \text{ln}(x) \). This means:
When we talk about logarithms and exponential functions, they are a classical example of inverse functions. The exponential function \( \text{e}^x \) is the inverse of the natural logarithm \( \text{ln}(x) \). This means:
- \( \text{ln}(\text{e}^x) = x \)
- \( \text{e}^{\text{ln}(x)} = x \)