Chapter 5: Problem 5
Let \(f\) be defined on \(\mathbb{R},\) and suppose that \(|f(x)-f(y)| \leq(x-y)^{2}\) for all \(x, y \in \mathbb{R} .\) Prove that \(f\) is a constant function.
Short Answer
Expert verified
Since \( |f(x) - f(y)| \leq (x-y)^2 \, \( \frac{f(x)-f(x+h)}{h} \) tends to 0 as \( h \to 0 \), which means \( f(x) \) is constant.
Step by step solution
01
- Show the difference constraint
Given the condition \( \lvert f(x) - f(y) \rvert \leq (x - y)^2 \), analyze how it affects the function's behavior at different points.
02
- Assume f(x) is not a constant
Suppose for the sake of contradiction that \( f(x) \eq f(y) \) for some \( x, y \in \mathbb{R} \).
03
- Consider the function at infinitesimal intervals
Take \( y = x + h \, \) where \( h \) is very small. The given condition becomes: \( \lvert f(x) - f(x + h) \rvert \leq h^2 \)
04
- Analyze the limit as h approaches 0
Dividing both sides of the inequality \( \lvert f(x) - f(x+h) \rvert \leq h^2 \) by \( h \, \) we get \( \lvert \frac{f(x) - f(x+h)}{h} \rvert \leq h \. \) As \( h \to 0 \), \( \frac{f(x) - f(x+h)}{h} \) must tend to 0 which implies the derivative of \( f \) is zero.
05
- Conclude that f is constant
If the derivative \( f'(x) = 0 \) for all x, it means \( f(x) \) must be a constant function. Thus, \( f(x) \) does not change and is constant.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
constant function
A **constant function** is a very simple but crucial concept in calculus and real analysis. A function \( f(x) \) is considered constant if, for any two points \( x \) and \( y \) in its domain, the function always produces the same value. Mathematically, this can be expressed as \( f(x) = f(y) \).
This means the function graph is a horizontal line.
These functions are important because they highlight the notion of rate of change.
In a constant function, the rate of change is zero, indicating that no matter how you move along the x-axis, the y-value remains unchanged.
This means the function graph is a horizontal line.
These functions are important because they highlight the notion of rate of change.
In a constant function, the rate of change is zero, indicating that no matter how you move along the x-axis, the y-value remains unchanged.
real analysis
**Real analysis** is a branch of mathematics that deals with real numbers and real-valued functions. In real analysis, we rigorously study various properties and behaviors of functions.
It involves concepts like sequences, limits, continuity, derivatives, and integrals.
This discipline provides a foundation for much of modern mathematics.
The problem at hand, concerning whether a function is constant, is rooted in real analysis.
The definition given in the problem, \( |f(x) - f(y)| \, \leq \, (x - y)^2 \), is an inequality that tells us about the behavior of \( f \) over the real numbers \( \mathbb{R} \).
This definition is part of understanding how functions behave more generally.
It involves concepts like sequences, limits, continuity, derivatives, and integrals.
This discipline provides a foundation for much of modern mathematics.
The problem at hand, concerning whether a function is constant, is rooted in real analysis.
The definition given in the problem, \( |f(x) - f(y)| \, \leq \, (x - y)^2 \), is an inequality that tells us about the behavior of \( f \) over the real numbers \( \mathbb{R} \).
This definition is part of understanding how functions behave more generally.
limit process
The **limit process** is an essential concept in calculus, which involves finding the value that a function approaches as the input approaches some point.
In our exercise, we used the limit process to analyze the behavior of \( f \) at extremely small intervals.
We considered \( y = x + h \) where \( h \) is very small.
This let us write the given condition as \( |f(x) - f(x + h)| \, \leq \, h^2 \).
By dividing both sides of this inequality by \( h \), we get \( |\frac{f(x) - f(x + h)}{h}| \, \leq \, h \). As \( h \) approaches zero, the term \( \frac{f(x) - f(x + h)}{h} \) needs to approach zero.
This is essentially finding the derivative and establishing that it must be zero, indicating no change in \( f \) and proving that \( f \) is constant.
In our exercise, we used the limit process to analyze the behavior of \( f \) at extremely small intervals.
We considered \( y = x + h \) where \( h \) is very small.
This let us write the given condition as \( |f(x) - f(x + h)| \, \leq \, h^2 \).
By dividing both sides of this inequality by \( h \), we get \( |\frac{f(x) - f(x + h)}{h}| \, \leq \, h \). As \( h \) approaches zero, the term \( \frac{f(x) - f(x + h)}{h} \) needs to approach zero.
This is essentially finding the derivative and establishing that it must be zero, indicating no change in \( f \) and proving that \( f \) is constant.
derivative
The **derivative** measures the rate at which a function changes as its input changes.
Mathematically, it is defined as:
\[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \]
In our given problem,
we started with \( |f(x) - f(x + h)| \, \leq \, h^2 \) and manipulated this inequality to find \( \frac{f(x) - f(x+h)}{h} \, \leq \, h \).
Taking the limit as \( h \) approaches zero,
the left-hand side, which is the definition of the derivative of \( f \) at \( x \), also approaches zero.
This implies \( f'(x) = 0 \).
If the derivative is zero for all \( x \), the function \( f \) must be constant across its domain.
Mathematically, it is defined as:
\[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \]
In our given problem,
we started with \( |f(x) - f(x + h)| \, \leq \, h^2 \) and manipulated this inequality to find \( \frac{f(x) - f(x+h)}{h} \, \leq \, h \).
Taking the limit as \( h \) approaches zero,
the left-hand side, which is the definition of the derivative of \( f \) at \( x \), also approaches zero.
This implies \( f'(x) = 0 \).
If the derivative is zero for all \( x \), the function \( f \) must be constant across its domain.
inequalities in calculus
Inequalities play a significant role in calculus by providing bounds and constraints on functions.
In our given exercise, the inequality \( |f(x) - f(y)| \, \leq \, (x - y)^2 \) helped to analyze the behavior of the function \( f \).
Understanding how small changes in \( x \) and \( y \) affect \( f(x) \) using inequalities enabled us to infer properties about the function.
These kinds of inequalities are essential for:
In our given exercise, the inequality \( |f(x) - f(y)| \, \leq \, (x - y)^2 \) helped to analyze the behavior of the function \( f \).
Understanding how small changes in \( x \) and \( y \) affect \( f(x) \) using inequalities enabled us to infer properties about the function.
These kinds of inequalities are essential for:
- Proving continuity
- Finding Lipschitz conditions
- Analyzing differentiability