Chapter 8: Problem 57
Contains the point \((-1,3)\) and is perpendicular to the line \(2 x-y=4\)
Short Answer
Expert verified
The equation of the line is \(x + 2y = 5\).
Step by step solution
01
Find the slope of the given line
The given line is represented by the equation \(2x - y = 4\). To find its slope, let's rearrange it into the slope-intercept form \(y = mx + b\). By solving for \(y\), we get \(y = 2x - 4\). Therefore, the slope of the given line, \(m_1\), is 2.
02
Determine the perpendicular slope
The slopes of perpendicular lines are negative reciprocals. Therefore, if the slope of the given line is \(m_1 = 2\), then the slope \(m_2\) of the line that is perpendicular to it will be \(-\frac{1}{2}\).
03
Write the equation of the perpendicular line
Use the point-slope form of the equation \(y - y_1 = m(x - x_1)\), where \(m\) is the slope and \((x_1, y_1)\) is a point on this line. The given point is \((-1, 3)\) and we found \(m = -\frac{1}{2}\). Apply these values to get: \[y - 3 = -\frac{1}{2}(x + 1)\].
04
Simplify the equation
Distribute the slope on the right side: \[y - 3 = -\frac{1}{2}x - \frac{1}{2}\].Add 3 to both sides to solve for \(y\): \[y = -\frac{1}{2}x - \frac{1}{2} + 3\].Combine constants: \[y = -\frac{1}{2}x + \frac{5}{2}\].
05
Express the equation in standard form
To convert the equation \(y = -\frac{1}{2}x + \frac{5}{2}\) to standard form, multiply through by 2 to eliminate fractions: \[2y = -x + 5\].Rearrange it to get \[x + 2y = 5\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form of a linear equation is one of the most popular ways to express the equation of a line. It is written as:- \( y = mx + b \)
Where:
Where:
- \( m \) represents the slope of the line.
- \( b \) is the y-intercept, the point where the line crosses the y-axis.
Point-Slope Form
Point-slope form is incredibly useful when you know a point on the line and the line's slope. This linear equation form is written as:- \( y - y_1 = m(x - x_1) \)
Where:
Where:
- \( m \) is the slope of the line.
- \((x_1, y_1)\) is a known point on the line.
Standard Form
The standard form is yet another way of expressing a linear equation. It is written as:- \( Ax + By = C \)
Where:
Where:
- \( A \), \( B \), and \( C \) are integers.
- \( A \) should be non-negative.
- When possible, \( A \), \( B \), and \( C \) should have no common divisors other than 1.