Chapter 8: Problem 5
For Problems 1-12, find the equation of the line that contains the given point and has the given slope. Express equations in the form \(A x+B y=C\), where \(A, B\), and \(C\) are integers. $$ (-4,8), m=-\frac{1}{3} $$
Short Answer
Expert verified
The equation of the line is \(x + 3y = 20\).
Step by step solution
01
Identify the Point-Slope Form
We start with the point-slope form of the equation of a line: \[ y - y_1 = m(x - x_1) \] where \((x_1, y_1)\) is the given point (-4, 8) and \(m = -\frac{1}{3}\) is the slope.
02
Substitute the Point and Slope into the Equation
Substitute the given point \((-4, 8)\) and the slope \(m = -\frac{1}{3}\) into the point-slope form:\[ y - 8 = -\frac{1}{3}(x + 4) \]
03
Simplify the Equation
Distribute the slope on the right-hand side:\[ y - 8 = -\frac{1}{3}x - \frac{4}{3} \]
04
Move Terms to Form an Equation in Ax + By = C
To remove fractions, multiply the entire equation by 3 to eliminate the fraction:\[ 3(y - 8) = -x - 4 \]Simplify and rearrange to the standard form:\[ 3y - 24 = -x - 4 \]
05
Rearrange to Standard Form
Move all terms to one side to get the standard form:\[ x + 3y = 20 \]This simplifies to the standard form of a linear equation with integer coefficients.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Point-Slope Form
The point-slope form is a convenient way to find the equation of a line when you know a point on the line and the slope of the line. The general formula for the point-slope form is \[ y - y_1 = m(x - x_1) \]Here,
For example, consider the point (-4, 8) and the slope \(-\frac{1}{3}\). By plugging these values into the point-slope form, you have:\[ y - 8 = -\frac{1}{3}(x + 4) \]This simple substitution quickly gets you started on forming the line's equation. From here, you can rearrange the equation into other forms, like the slope-intercept form or standard form, depending on your needs.
- \(x_1\) and \(y_1\) are the coordinates of the given point.
- \(m\) is the slope of the line.
For example, consider the point (-4, 8) and the slope \(-\frac{1}{3}\). By plugging these values into the point-slope form, you have:\[ y - 8 = -\frac{1}{3}(x + 4) \]This simple substitution quickly gets you started on forming the line's equation. From here, you can rearrange the equation into other forms, like the slope-intercept form or standard form, depending on your needs.
Standard Form
The standard form of a linear equation is expressed as \[ Ax + By = C \]where \(A\), \(B\), and \(C\) are integers. This form is useful because it provides a clear, structured way to present linear equations, allowing for easy comparison between different lines and straightforward solving of systems of equations.
- \(A\) and \(B\) should not both be zero.
- Typically, \(A\) is a non-negative integer, meaning \(A\) is positive or zero.
Slope-Intercept Form
The slope-intercept form of a linear equation is one of the most widely used forms due to its simplicity and clarity. It is given by:\[ y = mx + b \]where
- \(m\) represents the slope of the line.
- \(b\) represents the y-intercept, or the point where the line crosses the y-axis.