Chapter 6: Problem 63
$$ \text { For Problems } 61-84 \text {, solve each equation. (Objective 4) } $$ $$ x^{2}+x=0 $$
Short Answer
Expert verified
The solutions are \( x = 0 \) and \( x = -1 \).
Step by step solution
01
Identify the Equation Type
The equation given is a quadratic equation, which typically takes the form \( ax^2 + bx + c = 0 \). In this case, \( a = 1 \), \( b = 1 \), and \( c = 0 \).
02
Factor the Quadratic Equation
Rewrite the equation \( x^2 + x = 0 \) by factoring out the common term \( x \). The factored form is \( x(x + 1) = 0 \).
03
Apply the Zero-Product Property
The zero-product property states that if \( ab = 0 \), then either \( a = 0 \) or \( b = 0 \). Apply this property to the factored equation: \( x = 0 \) or \( x + 1 = 0 \).
04
Solve Each Factored Equation
Solve each equation from Step 3:- For \( x = 0 \), the solution is straightforward: \( x = 0 \).- For \( x + 1 = 0 \), subtract 1 from both sides to solve for \( x \): \( x = -1 \).
05
State the Solutions
The solutions to the equation \( x^2 + x = 0 \) are \( x = 0 \) and \( x = -1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring Quadratic Equations
Factoring quadratic equations involves rewriting the equation in a form that is easier to solve. Quadratic equations usually have the structure \( ax^2 + bx + c = 0 \). Here, the goal is to express the quadratic as a product of two binomials. In simpler cases, like in the equation \( x^2 + x = 0 \), you can use common factoring methods.
**What is Common Factoring?**
In the exercise example, the equation \( x^2 + x = 0 \) can be factored by identifying the common factor in each term. Notice that \( x \) is the common factor in both terms.
- First term: \( x^2 \) has \( x \) as a factor.
- Second term: \( x \) is obviously present.
By factoring out \( x \), we get \( x(x + 1) = 0 \). This step is crucial, as it prepares the equation for the next solving stage, using the Zero-Product Property.
**What is Common Factoring?**
In the exercise example, the equation \( x^2 + x = 0 \) can be factored by identifying the common factor in each term. Notice that \( x \) is the common factor in both terms.
- First term: \( x^2 \) has \( x \) as a factor.
- Second term: \( x \) is obviously present.
By factoring out \( x \), we get \( x(x + 1) = 0 \). This step is crucial, as it prepares the equation for the next solving stage, using the Zero-Product Property.
Zero-Product Property
The Zero-Product Property is a fundamental concept used in solving factored quadratic equations. This property states that if the product of two numbers is zero, then at least one of the numbers must be zero.
**Applying the Zero-Product Property:**
Once you have your equation in factored form, like \( x(x + 1) = 0 \), you can apply this property.
- For the product to equal zero, set each factor to zero. You break it into two separate equations: \( x = 0 \) and \( x + 1 = 0 \).
- Solve these simpler equations independently.
This step reduces a possibly complex quadratic equation into more manageable linear equations, making it simpler to find the solutions.
**Applying the Zero-Product Property:**
Once you have your equation in factored form, like \( x(x + 1) = 0 \), you can apply this property.
- For the product to equal zero, set each factor to zero. You break it into two separate equations: \( x = 0 \) and \( x + 1 = 0 \).
- Solve these simpler equations independently.
This step reduces a possibly complex quadratic equation into more manageable linear equations, making it simpler to find the solutions.
Quadratic Equation Solutions
Once the quadratic equation is factored and the Zero-Product Property is applied, the solutions are found. These are the values of \( x \) that satisfy the original equation after going through the previous steps.
**Solution Process:**
From the equations \( x = 0 \) and \( x + 1 = 0 \), solve each one to get the solutions:
The final solutions of the quadratic equation \( x^2 + x = 0 \) are \( x = 0 \) and \( x = -1 \). These are the values that satisfy the original equation, representing where the function crosses or touches the x-axis on a graph.
**Solution Process:**
From the equations \( x = 0 \) and \( x + 1 = 0 \), solve each one to get the solutions:
- For \( x = 0 \), it's straightforward—this is already a solution.
- For \( x + 1 = 0 \), subtract 1 from both sides to find \( x = -1 \).
The final solutions of the quadratic equation \( x^2 + x = 0 \) are \( x = 0 \) and \( x = -1 \). These are the values that satisfy the original equation, representing where the function crosses or touches the x-axis on a graph.