Chapter 6: Problem 58
$$ \text { For Problems 45-68, solve each equation. (Objective 2) } $$ $$ x^{3}-x=0 $$
Short Answer
Expert verified
The solutions are \(x = 0\), \(x = 1\), and \(x = -1\).
Step by step solution
01
Identify and Simplify Given Equation
The given equation is \(x^3 - x = 0\). We can notice that both terms on the left side of the equation have a common factor, \(x\).
02
Factoring Out the Common Factor
Factor out the common factor \(x\) from the terms on the left side: \(x(x^2 - 1) = 0\).
03
Solve Each Factor for Zero
Solve each factor set to zero to find the possible solutions. The first factor gives us an immediate solution: \(x = 0\).
04
Solve the Quadratic Factor
The second factor, \(x^2 - 1 = 0\), is a quadratic equation. To solve it, we can use the difference of squares: \((x - 1)(x + 1) = 0\).
05
Find the Roots of the Quadratic Factor
Set each expression of the quadratic factor to zero: \(x - 1 = 0\) gives \(x = 1\), and \(x + 1 = 0\) gives \(x = -1\).
06
Compile All Solutions
Combine all solutions from the previous steps: the solutions to the equation are \(x = 0\), \(x = 1\), and \(x = -1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring
Factoring is a method used in algebra to simplify expressions, solve equations, and find roots of polynomial equations. It involves breaking down a complex expression into a set of simpler multiplicative components called factors. In the equation \( x^3 - x = 0 \), factoring plays a crucial role in solving for \( x \).Here's how factoring works:
- Identify the greatest common factor (GCF) in the expression, which is the largest expression that divides all terms evenly.
- Divide each term by the GCF, and express the original equation as a product of the GCF and another polynomial.
Quadratic Equations
Quadratic equations play a significant part in algebra and appear frequently in problems requiring factoring and solving polynomial equations. A quadratic equation is generally of the form \( ax^2 + bx + c = 0 \). Solving it involves finding values of \( x \) that satisfy the equation.When given the equation \( x^2 - 1 = 0 \), we're dealing with a quadratic equation because it involves \( x^2 \), the highest degree is 2.Quadratic equations can be solved using different methods:
- Factoring, by expressing the equation as a product of two binomials, if possible.
- Using the quadratic formula: \( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \).
- Completing the square, which involves rearranging the equation into a perfect square trinomial.
Difference of Squares
Understanding the difference of squares is essential to efficiently solve and factor certain algebraic expressions. In algebra, a difference of squares is a specific form of a binomial known as \( a^2 - b^2 \), which can be factored into \( (a - b)(a + b) \).This pattern is incredibly useful because it allows us to solve equations like \( x^2 - 1 = 0 \) much faster than alternative methods.The expression \( x^2 - 1 \) is indeed a difference of squares, where:
- \( a^2 = x^2 \) hence \( a = x \).
- \( b^2 = 1 \) hence \( b = 1 \).