Chapter 6: Problem 52
$$ \text { For Problems 51-80, solve each equation. (Objective 2) } $$ $$ 3 x^{2}+16 x+5=0 $$
Short Answer
Expert verified
The solutions are \( x = -\frac{1}{3} \) and \( x = -5 \).
Step by step solution
01
Recognize the Equation Form
The given equation is a quadratic equation of the form \( ax^2 + bx + c = 0 \) where \( a = 3 \), \( b = 16 \), and \( c = 5 \).
02
Apply the Quadratic Formula
For the quadratic equation \( ax^2 + bx + c = 0 \), the roots can be found using the quadratic formula: \( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} \).
03
Compute the Discriminant
Calculate the discriminant \( b^2 - 4ac \). Substitute the values \( b = 16 \), \( a = 3 \), and \( c = 5 \) into the discriminant formula: \( 16^2 - 4 \, \cdot \, 3 \, \cdot \, 5 = 256 - 60 = 196 \).
04
Solve for the Roots
Substitute the values back into the quadratic formula: \( x = \frac{{-16 \pm \sqrt{196}}}{6} \). Since \( \sqrt{196} = 14 \), the equation becomes \( x = \frac{{-16 \pm 14}}{6} \).
05
Calculate Each Solution
Calculate the two possible solutions:1. Using \( +14 \): \( x_1 = \frac{{-16 + 14}}{6} = \frac{{-2}}{6} = -\frac{1}{3} \).2. Using \( -14 \): \( x_2 = \frac{{-16 - 14}}{6} = \frac{{-30}}{6} = -5 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a universal tool for solving equations of the form \( ax^2 + bx + c = 0 \). It provides a straightforward method to find the roots or solutions of a quadratic equation. The formula itself is given by:
- \( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} \)
- \( a \) represents the coefficient of \( x^2 \)
- \( b \) is the coefficient of \( x \)
- \( c \) is the constant term
Discriminant
The discriminant is an essential component of the quadratic formula, found under the square root part, \( \sqrt{{b^2 - 4ac}} \). It helps in determining the nature of the roots of the quadratic equation. The discriminant \( D \) is calculated as follows:
\[ D = b^2 - 4ac \]
The value of the discriminant reveals key insights:
\[ D = b^2 - 4ac \]
The value of the discriminant reveals key insights:
- If \( D > 0 \), there are two distinct real roots. This suggests the parabola intersects the x-axis at two points.
- If \( D = 0 \), there is exactly one real root or double root. The parabola just touches the x-axis, creating a single point of intersection.
- If \( D < 0 \), the equation has two complex roots, indicating no real x-intercepts. The parabola does not intersect the x-axis at all.
Roots of Equation
The roots of a quadratic equation are the values of \( x \) that make the equation equal to zero. These are essentially the solutions we seek when solving quadratics of the form \( ax^2 + bx + c = 0 \). By using the quadratic formula, you can find these roots as follows:
- First, calculate the discriminant \( D \) to understand the nature of the roots.
- Next, plug the values into the quadratic formula to determine \( x \).
- This results in two potential roots, expressed as \( x_1 = \frac{{-b + \sqrt{D}}}{2a} \) and \( x_2 = \frac{{-b - \sqrt{D}}}{2a} \).