Chapter 11: Problem 22
Solve each of the following quadratic equations, and check your solutions. $$3 x^{2}-5 x-2=0$$
Short Answer
Expert verified
The solutions are \( x = 2 \) and \( x = -\frac{1}{3} \).
Step by step solution
01
Identify a, b, and c
The given quadratic equation is in the standard form \( ax^2 + bx + c = 0 \), which is \( 3x^2 - 5x - 2 = 0 \). From this equation, identify \( a = 3 \), \( b = -5 \), and \( c = -2 \).
02
Calculate the Discriminant
The discriminant \( D \) is calculated using the formula \( b^2 - 4ac \). Here, \( b = -5 \), \( a = 3 \), and \( c = -2 \). Calculate \( (-5)^2 - 4 \times 3 \times (-2) = 25 + 24 = 49 \).
03
Apply the Quadratic Formula
Use the quadratic formula \( x = \frac{-b \pm \sqrt{D}}{2a} \) to find the roots. Substitute \( b = -5 \), \( a = 3 \), and \( \sqrt{D} = 7 \) into the formula:\[ x = \frac{-(-5) \pm 7}{2 \times 3} = \frac{5 \pm 7}{6} \]This gives two solutions: \( x_1 = \frac{5 + 7}{6} \) and \( x_2 = \frac{5 - 7}{6} \).
04
Simplify the Solutions
Simplify the solutions obtained from the quadratic formula.For \( x_1 \), calculate \( \frac{12}{6} = 2 \).For \( x_2 \), calculate \( \frac{-2}{6} = -\frac{1}{3} \).Therefore, the solutions are \( x = 2 \) and \( x = -\frac{1}{3} \).
05
Verify the Solutions
Substitute \( x = 2 \) back into the original equation: \( 3(2)^2 - 5(2) - 2 = 12 - 10 - 2 = 0 \).Next, substitute \( x = -\frac{1}{3} \): \( 3(-\frac{1}{3})^2 - 5(-\frac{1}{3}) - 2 = \frac{1}{3} + \frac{5}{3} - 2 = 0 \).Both solutions satisfy the original equation, confirming that \( x = 2 \) and \( x = -\frac{1}{3} \) are correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
In the context of quadratic equations, the discriminant is a powerful tool that helps us determine the nature of the roots without solving the equation completely. Every quadratic equation is in the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants. The discriminant \( D \) is given by the formula:
- \( D = b^2 - 4ac \)
- If \( D > 0 \), the quadratic equation has two distinct real roots.
- If \( D = 0 \), there is exactly one real root, which is also called a repeated or double root.
- If \( D < 0 \), there are no real roots, but two complex roots.
Quadratic Formula
The quadratic formula is a crucial tool for finding solutions of quadratic equations. This formula allows you to directly calculate the roots without the need to factor the equation. The formula is expressed as:
For the quadratic equation \( 3x^2 - 5x - 2 = 0 \), by substituting \( a = 3 \), \( b = -5 \), and the discriminant \( \sqrt{49} = 7 \) into the formula, we can find the roots:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
For the quadratic equation \( 3x^2 - 5x - 2 = 0 \), by substituting \( a = 3 \), \( b = -5 \), and the discriminant \( \sqrt{49} = 7 \) into the formula, we can find the roots:
- \( x_1 = \frac{5 + 7}{6} = 2 \)
- \( x_2 = \frac{5 - 7}{6} = -\frac{1}{3} \)
Solving Quadratic Equations
Solving quadratic equations is a fundamental aspect of algebra, often involving methods like factoring, completing the square, or the quadratic formula. It is through solving these equations that we uncover the values of \( x \) that satisfy \( ax^2 + bx + c = 0 \). Here’s a simple process to tackle a quadratic equation using the quadratic formula:
- Identify \( a \), \( b \), and \( c \) from the given equation.
- Calculate the discriminant \( b^2 - 4ac \).
- Apply the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
- Solve for \( x \) by computing both the addition and subtraction parts.