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For Problems \(1-12\), write each radical in terms of \(i\) and simplify; for example, \(\sqrt{-20}=i \sqrt{20}=i \sqrt{4} \cdot \sqrt{5}=\) \(2 i \sqrt{5}\) $$ \sqrt{-28} $$

Short Answer

Expert verified
\( \sqrt{-28} = 2i \sqrt{7} \).

Step by step solution

01

Express Negative Radical Using i

Given \ \( \sqrt{-28} \), recognize that this expression involves a square root of a negative number. We apply the identity \( \sqrt{-1} = i \). Hence, \( \sqrt{-28} = \sqrt{-1} \cdot \sqrt{28} = i \sqrt{28} \).
02

Simplify the Square Root of Positive Part

Next, we simplify \( \sqrt{28} \). Break 28 into its prime factors: \( 28 = 4 \cdot 7 \). Since \( 4 \) is a perfect square, we can rewrite \( \sqrt{28} \) as \( \sqrt{4 \cdot 7} = \sqrt{4} \cdot \sqrt{7} = 2 \sqrt{7} \).
03

Combine Terms

Substitute back to the expression from Step 1: \( i \sqrt{28} = i \cdot 2 \sqrt{7} = 2i \sqrt{7} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Numbers
Imaginary numbers are an essential concept in mathematics, especially when dealing with square roots of negative numbers. They help us expand our understanding beyond real numbers. The fundamental imaginary unit is denoted as \(i\), defined by the property \(i^2 = -1\). This definition allows us to express the square root of negative numbers in terms of imaginary numbers.
For instance, to express \(\sqrt{-28}\) in terms of \(i\), you can break it down using \(\sqrt{-1} = i\). Thus, \(\sqrt{-28} = \sqrt{-1} \times \sqrt{28}\), simplifying to \(i \sqrt{28}\). This conversion forms the basis for solving problems involving negative square roots. Understanding how to utilize \(i\) in this way allows complex numbers, which are combinations of real and imaginary components, to be treated algebraically just like real numbers.
Simplifying Radicals
Simplifying radicals involves the process of making a square root expression easier to handle without changing its value. Consider breaking down the expression inside the radical into its prime factors to identify perfect squares. This makes simplifying radicals much easier and more systematic.
In the problem \(\sqrt{28}\), you start by factoring \(28\) as \(4 \times 7\). Knowing that \(4\) is a perfect square, rewrite \(\sqrt{28}\) as \(\sqrt{4 \times 7}\). We can then easily simplify this further to \(\sqrt{4} \cdot \sqrt{7}\), giving \(2 \sqrt{7}\).
By recognizing and utilizing perfect squares within the expression, the simplified radical \(2 \sqrt{7}\) is reached, which is a more manageable form. Simplifying radicals is a key skill to make complex expressions more understandable and to prepare them for further computations.
Perfect Squares
Perfect squares greatly aid in the simplification of radicals. A perfect square is a number that can be expressed as the product of an integer by itself. Examples include \(1, 4, 9, 16,\) and so on. Using perfect squares can simplify expressions, particularly those involving square roots.
When looking to simplify \(\sqrt{28}\), identify perfect square factors of \(28\). Since \(4\) is a perfect square (\(2 \times 2\)), it can be "extracted" from under the square root, simplifying it to \(2 \sqrt{7}\). This showcases the usefulness of spotting perfect squares: they simplify calculations and make it easier to understand the mathematical expression.
By recognizing perfect square factors such as \(4\) in expressions like \(\sqrt{28}\), complex expressions become more manageable. This insight also aids in algebraic transformations, making it a fundamental aspect of manipulating and working with complex numbers.

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Most popular questions from this chapter

To charge, in dollars, for children's meals, a restaurant uses the function \(f(x)=0\) when the child is less than 2 years old, and the function \(g(x)=0.50 x\) when the child's age is 2 or more, where \(x\) is the age of the child. How much does a child's meal cost for an 8-year-old child, a 3-yearold child, a 1-year-old child, and a 12 -year-old child?

The function \(f(t)=\frac{5}{9}(t-32)\) expresses the temperature in degrees Celsius as a function of the temperature in degrees Fahrenheit. (a) Use the function to complete the table. $$ \begin{array}{l|l|l|l|l|l|l|l} \hline t & 50 & 41 & -4 & 212 & 95 & 77 & 59 \\ \hline \boldsymbol{f}(t) & & & & & & & \\ \hline \end{array} $$ (b) Graph the linear function \(f(t)=\frac{5}{9}(t-32)\). (c) Use the graph from part (b) to approximate the temperature in degrees Celsius when the temperature is \(20^{\circ} \mathrm{F}\). Then use the function to find the exact value.

For Problems \(13-34\), add or subtract the complex numbers as indicated. $$ (-2-i)-(3-4 i) $$

The volume, in cubic inches, of a right circular cylinder with a fixed base can be expressed as the function \(V(h)=201 h\), where \(h\) is the height of the cylinder in inches. Determine the volume of a cylinder that is 12 inches high.

Wesley owns 1000 shares of stock. He is considering selling some of it, and he knows his profit can be represented by the function \(f(x)=28 x-150\), where \(x\) is the number of shares sold. Create a table showing the profit for selling \(100,200,400,500\), or 600 shares.

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