Chapter 10: Problem 6
\(x^{2}+6 x-11=0\)
Short Answer
Expert verified
The solutions are \(x = -3 + 2\sqrt{5}\) and \(x = -3 - 2\sqrt{5}\).
Step by step solution
01
Understand the Equation
The given quadratic equation is \(x^2 + 6x - 11 = 0\). It is in the standard form of a quadratic equation \(ax^2 + bx + c = 0\), where \(a = 1\), \(b = 6\), and \(c = -11\).
02
Identify the Method
Since the equation does not easily factor, we will use the quadratic formula to find the roots of the equation. The quadratic formula is \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
03
Calculate the Discriminant
Calculate the discriminant \(b^2 - 4ac\). Here, \(b = 6\), \(a = 1\), and \(c = -11\), so: \(b^2 - 4ac = 6^2 - 4 \times 1 \times (-11) = 36 + 44 = 80\).
04
Apply the Quadratic Formula
Since the discriminant is positive, we proceed with the quadratic formula: \(x = \frac{-6 \pm \sqrt{80}}{2}\). Simplify \(\sqrt{80}\) to \(4\sqrt{5}\), so the formula becomes \(x = \frac{-6 \pm 4\sqrt{5}}{2}\).
05
Simplify the Expression
Simplify \(x = \frac{-6 \pm 4\sqrt{5}}{2}\) by dividing each term by 2: \(x = -3 \pm 2\sqrt{5}\). This gives the two solutions \(x = -3 + 2\sqrt{5}\) and \(x = -3 - 2\sqrt{5}\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
quadratic formula
The quadratic formula is a powerful tool for solving any quadratic equation, given by the form \( ax^2 + bx + c = 0 \). It is represented as:
Every quadratic equation has two solutions that may be real or complex numbers, depending on the discriminant. The '±' symbol indicates that there can be two different outcomes, adding depth to the solution possibilities.
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Every quadratic equation has two solutions that may be real or complex numbers, depending on the discriminant. The '±' symbol indicates that there can be two different outcomes, adding depth to the solution possibilities.
discriminant
The discriminant is a critical component of the quadratic formula, found within the square root: \( b^2 - 4ac \). It tells us much about the nature of the roots without having to solve entirely.
- If \( b^2 - 4ac > 0 \), the quadratic equation has two distinct real roots.
- If \( b^2 - 4ac = 0 \), there is exactly one real root, also known as a repeated or double root.
- If \( b^2 - 4ac < 0 \), there are no real roots; instead, the equation has two complex roots.
standard form of quadratic equations
The standard form for a quadratic equation is \( ax^2 + bx + c = 0 \). Each coefficient in the expression provides important information.
- \( a \): The leading coefficient, which impacts the parabola's width and direction.
- \( b \): Affects the location of the parabola along the x-axis.
- \( c \): Represents the y-intercept, or where the parabola cuts the y-axis.
solving quadratic equations
Solving quadratic equations involves finding the "roots," the values of \( x \) where \( ax^2 + bx + c = 0 \). There are several methods:
The steps involve:
- Factoring - suitable when the equation easily breaks into products of simpler expressions.
- Completing the Square - works for any equation but may be cumbersome compared to other methods.
- Quadratic Formula - a universal method that applies when other methods are complex or infeasible.
The steps involve:
- Identify coefficients \( a \), \( b \), and \( c \).
- Calculate the discriminant \( b^2 - 4ac \).
- Apply the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).