Chapter 10: Problem 34
Solve each of the following quadratic equations using the method that seems most appropriate to you. $$x+\frac{1}{x}=\frac{65}{8}$$
Short Answer
Expert verified
\( x_1 = \frac{65 + \sqrt{129}}{16} \) and \( x_2 = \frac{65 - \sqrt{129}}{16} \).
Step by step solution
01
Identify Equation Form
The given equation \( x + \frac{1}{x} = \frac{65}{8} \) is not in standard quadratic form. We need to manipulate it into a quadratic equation.
02
Eliminate the Fraction
Multiply both sides of the equation by \( x \) to eliminate the fraction, resulting in \( x^2 + 1 = \frac{65}{8}x \).
03
Rearrange to Form Quadratic Equation
Rearrange the equation to standard quadratic form by moving all terms to one side: \( x^2 - \frac{65}{8}x + 1 = 0 \).
04
Calculate the Discriminant
Calculate the discriminant (\( \Delta \)) of the quadratic equation \( \Delta = b^2 - 4ac \). Here, \( a = 1 \), \( b = -\frac{65}{8} \), and \( c = 1 \). So, \( \Delta = \left(-\frac{65}{8}\right)^2 - 4 \times 1 \times 1 \).
05
Solve for Roots
Calculate \( \Delta \): \( \Delta = \frac{4225}{64} - 4 = \frac{4096}{64} \).Thus, \( \Delta = \frac{129}{64} \). Next, apply the quadratic formula \( x = \frac{-b \pm \sqrt{\Delta}}{2a} \).
06
Evaluate Square Root and Simplify
Calculate the square root: \( \sqrt{\frac{129}{64}} = \frac{\sqrt{129}}{8} \). Now substitute back into the quadratic formula to get two solutions: \( x_1 = \frac{\frac{65}{8} + \frac{\sqrt{129}}{8}}{2} \) and \( x_2 = \frac{\frac{65}{8} - \frac{\sqrt{129}}{8}}{2} \).
07
Final Calculation of Solutions
Calculate \( x_1\) and \( x_2\):\( x_1 = \frac{65 + \sqrt{129}}{16} \) and \( x_2 = \frac{65 - \sqrt{129}}{16} \). These are the solutions of the equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solving Quadratic Equations
To solve a quadratic equation means finding the values of the variable (usually denoted as \( x \)) that make the quadratic expression equal to zero. Quadratic equations have the general form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \).
Quadratic equations can be solved using several methods:
Quadratic equations can be solved using several methods:
- Factoring: If a quadratic equation can be factored easily, this method is quick. Find two numbers that multiply to give \( ac \) (the product of \( a \) and \( c \)) and add to give \( b \).
- Completing the Square: This involves rearranging the equation so the expression in \( x \) becomes a perfect square trinomial.
- Graphing: Sometimes, simply graphing the equation can reveal the roots as the points where the graph crosses the \( x \)-axis.
- Quadratic Formula: This method can always solve any quadratic equation and involves using the formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
Discriminant of Quadratic Equations
The discriminant is a significant part of the quadratic formula and is given by the expression \( b^2 - 4ac \) in the quadratic equation \( ax^2 + bx + c = 0 \). The discriminant helps determine the nature of the roots of a quadratic equation.
Here's how it works:
Here's how it works:
- Positive Discriminant (\( \Delta > 0 \)): Indicates that the quadratic equation has two distinct real roots.
- Zero Discriminant (\( \Delta = 0 \)): Means there is exactly one real root. The quadratic "touches" the \( x \)-axis but does not cross it.
- Negative Discriminant (\( \Delta < 0 \)): Suggests there are no real roots, but two complex (or imaginary) roots.
Quadratic Formula
The quadratic formula provides a universal solution method for finding the roots of any quadratic equation \( ax^2 + bx + c = 0 \). It is expressed as:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula stems from completing the square for a general quadratic equation and offers explicit solutions for \( x \) based on the coefficients \( a \), \( b \), and \( c \).
Steps to Use the Quadratic Formula:
This process showcases the power of the quadratic formula for solving equations efficiently, especially when other methods like factoring do not readily apply.
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula stems from completing the square for a general quadratic equation and offers explicit solutions for \( x \) based on the coefficients \( a \), \( b \), and \( c \).
Steps to Use the Quadratic Formula:
- Identify the coefficients \( a \), \( b \), and \( c \) from the quadratic equation.
- Calculate the discriminant \( \Delta = b^2 - 4ac \).
- Plug \( b \), \( \Delta \), and \( a \) into the quadratic formula.
- Simplify to find the values of \( x \).
This process showcases the power of the quadratic formula for solving equations efficiently, especially when other methods like factoring do not readily apply.