Chapter 10: Problem 33
\(x^{2}+4 x-12=0\)
Short Answer
Expert verified
The solutions are \(x = 2\) and \(x = -6\).
Step by step solution
01
Identify the Form of the Equation
The given equation is a quadratic equation in the form of \(ax^2 + bx + c = 0\), where \(a = 1\), \(b = 4\), and \(c = -12\).
02
Apply the Quadratic Formula
To find the solutions of the quadratic equation, we use the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). Substitute \(a = 1\), \(b = 4\), and \(c = -12\) into the formula.
03
Calculate the Discriminant
Calculate the discriminant \(b^2 - 4ac\). Here, \(b^2 = 16\) and \(-4ac = 48\). So, the discriminant is \(16 + 48 = 64\).
04
Find the Roots
Using the quadratic formula, substitute into \(x = \frac{-4 \pm \sqrt{64}}{2}\). Since \(\sqrt{64} = 8\), the roots are \(x = \frac{-4 + 8}{2}\) and \(x = \frac{-4 - 8}{2}\).
05
Simplify the Roots
Simplify the expressions for the roots: \(x = \frac{4}{2} = 2\) and \(x = \frac{-12}{2} = -6\). The solutions to the equation are \(x = 2\) and \(x = -6\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for finding the roots of any quadratic equation. A quadratic equation is typically of the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. The quadratic formula specifically allows us to calculate the values of \(x\) that satisfy the equation. Here's what the formula looks like:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Discriminant
The discriminant is the part of the quadratic formula under the square root: \(b^2 - 4ac\). The value of the discriminant provides crucial information about the nature of the roots of a quadratic equation.
- If the discriminant is positive, the equation has two distinct real roots.
- If it is zero, the equation has exactly one real root, also known as a repeated or double root.
- If the discriminant is negative, the equation has two complex roots, which are not real numbers.
Roots of a Quadratic Equation
The roots of a quadratic equation are the values of \(x\) that make the equation true, essentially where the graph of the equation will cross the \(x\)-axis. Using the quadratic formula provides a systematic method to find these roots. In our specific problem, the roots of the equation \(x^2 + 4x - 12 = 0\) come from substituting the values into the formula:
- \(x = \frac{-4 \pm \sqrt{64}}{2}\)
- \(\sqrt{64} = 8\), giving us \(x = \frac{-4 + 8}{2} = 2\) and \(x = \frac{-4 - 8}{2} = -6\)