Chapter 10: Problem 25
Use the quadratic formula to solve each of the following quadratic equations. $$5 x^{2}+3 x-2=0$$
Short Answer
Expert verified
The solutions are \( x = \frac{2}{5} \) and \( x = -1 \).
Step by step solution
01
Identify the coefficients
The given quadratic equation is \(5x^2 + 3x - 2 = 0\). Identify the coefficients from this equation: \(a = 5\), \(b = 3\), and \(c = -2\).
02
State the quadratic formula
The quadratic formula is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] This formula is used to find the roots of the quadratic equation \(ax^2 + bx + c = 0\).
03
Calculate the discriminant
The discriminant \(D\) is calculated using the formula \(D = b^2 - 4ac\). Substitute the identified coefficients: \[ D = 3^2 - 4(5)(-2) = 9 + 40 = 49 \]
04
Evaluate the square root of the discriminant
Since \(D = 49\), evaluate the square root: \(\sqrt{49} = 7\).
05
Apply the quadratic formula to find the roots
Substitute the values of \(b\), \(\sqrt{D}\), and \(a\) into the quadratic formula: \[ x = \frac{-3 \pm 7}{2(5)} = \frac{-3 \pm 7}{10} \] This gives the two possible solutions for \(x\).
06
Calculate the solutions
Solve for the two values of \(x\): 1. \(x_1 = \frac{-3 + 7}{10} = \frac{4}{10} = \frac{2}{5}\) 2. \(x_2 = \frac{-3 - 7}{10} = \frac{-10}{10} = -1\)
07
Conclude the solutions
The solutions to the quadratic equation \(5x^2 + 3x - 2 = 0\) are \(x = \frac{2}{5}\) and \(x = -1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Quadratic Equations
A quadratic equation is a polynomial equation of the second degree. That means its highest exponent on the variable is two. Typically, these equations take the form \( ax^2 + bx + c = 0 \). Here, \( a \), \( b \), and \( c \) are constants, with \( a eq 0 \). Quadratic equations can have real or complex solutions, and they are best visualized as parabolas when graphed on a coordinate plane.
Some key elements to keep in mind are:
Some key elements to keep in mind are:
- The quadratic term: \( ax^2 \), which defines the parabola's "width" and orientation.
- The linear term: \( bx \), which affects the parabola's direction.
- The constant term: \( c \), which determines the parabola's vertical position on the y-axis.
What is the Discriminant?
The discriminant is a key component of the quadratic formula. It's a part of the formula that helps determine the nature of the roots of the equation. It is expressed as \( D = b^2 - 4ac \). This value is crucial because it tells us:
- If \( D > 0 \): The equation has two distinct real roots.
- If \( D = 0 \): The equation has exactly one real root (also known as a repeated or double root).
- If \( D < 0 \): The equation has two complex roots, which means they are not real numbers.
Finding the Roots of Quadratic Equations
The roots of a quadratic equation are the solutions for \( x \) in \( ax^2 + bx + c = 0 \). They are the values where the parabola crosses the x-axis on a graph. These can be found using the quadratic formula:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula channelizes the coefficients \( a \), \( b \), and \( c \) directly from the quadratic equation to find the roots.
Key steps involved include:
Key steps involved include:
- Calculating the discriminant, \( D \).
- Finding the square root of \( D \).
- Plugging the values into the quadratic formula.
- Solving for the potential \( x \) values.