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Chapter 5: Q.126 (page 626)

In the following exercises, solve the systems of equations by elimination.

5x+2y=2-3x-y=0

Short Answer

Expert verified

The solution of the system is(x,y)=(-2,6).

Step by step solution

01

Step 1. Given information

The given system is5x+2y=2-3x-y=0

02

Step 2. solve for x

5x+2y=2-3x-y=0Given5x+2y=22(-3x-y)=2(0)Mutiplyonbothsideswith25x+2y=2-6x-2y=0Simplify

Add both equations

5x+2y=2-6x-2y=0-x=2Solveforxx=-2

03

Step 3. solve for y

5x+2y=2firstequation5(-2)+2y=2Usex=-2-10+2y=22y=2+102y=12y=122y=6

Hence,(x,y)=(-2,6)

04

Step 4. verify the solution

5x+2y=2鈬�5(-2)+2(6)=2-10+12=22=2true-3x-y=0鈬�-3(-2)-6=06-6=00=0true

Both equations are true.

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