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Chapter 5: Q. 398 (page 683)

In the following exercises, solve each system of equations. Use either substitution or elimination.

2x+3y=12鈭�4x+6y=鈭�16

Short Answer

Expert verified

x=5andy=23

Step by step solution

01

Step 1. Given Information 

In the given exercises we have to solve given system of equations using either substitution or elimination method.

2x+3y=12鈭�4x+6y=鈭�16

02

Step 2. Solve the equations

2x+3y=12鈥�鈥�鈥�鈥�鈥�鈥�鈥�Equation1鈭�4x+6y=鈭�16鈥�鈥�鈥�鈥�鈥�Equation2

Using the elimination method to solve the equation.

Multiply the Equation 1 by 2

22x+3y=12脳24x+6y=24鈥�鈥�鈥�鈥�鈥�鈥�鈥�Equation3

03

Add Equation 3 and Equation 2.

4x+6y鈭�4x+6y=24鈭�1612y=8y=812y=23

Now substitutey=23in2x+3y=12

2x+323=122x+2=122x=12-22x=10x=5

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