/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 281 In the following exercises, dete... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In the following exercises, determine whether each ordered pair is a solution to the system.

2x+3y≥24x-6y<-1a.(32,43)b.(14,76)

Short Answer

Expert verified

Part (a) The ordered pair is a solution to the set.

Part (b) The ordered pair is a solution to the set.

Step by step solution

01

Part a. Step 1. Given Information

The given set is 2x+3y≥24x-6y<-1and the ordered pair is(32,43).

02

Part a. Step 2. Substitute the values into the inequalities.  

  • Substitute x=32,y=43into the first given inequality.

2(32)+3(43)≥?23+4≥?27≥2true

  • Substitute x=32,y=43into the second inequality.

4(32)-6(43)<?-16-8<?-1-2<-1true

  • Since both of the inequalities are satisfied, the given ordered pair is a solution to the system.
03

Part b. Step 1. Given Information

The given set is2x+3y≥24x-6y<-1and the ordered pair is(14,76).

04

Part b. Step 2. Substitute the values into the inequalities    

  • Substitute x=14,y=76into the first given inequality.

2(14)+3(76)≥?212+72≥?24≥2true

  • Substitute x=14,y=76into the second given inequality.

4(14)-6(76)<?-11-7<?-1-6<-1True

  • Since both of the inequalities are satisfied, the given ordered pair is a solution to the system.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.