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Chapter 2: Q. 48 (page 216)

In the following exercise, solve each equation.

鈭�(23d鈭�13)+53d=鈭�4

Short Answer

Expert verified

d=-133

Step by step solution

01

Step 1. Given information

In the following exercise, solve each equation.

鈭�(23d鈭�13)+53d=鈭�4

02

Step 2. Explanation

Simplify鈬�鈭�(23d鈭�13)+53d=鈭�4鈬�鈭�23d+13+53d=鈭�4Distributeontheleft鈬�鈭�23d+53d+13=鈭�4UsetheCommutativePropertytorearrangeterms.鈬�鈭�23d+53d+13=鈭�4CombineliketermsandtakingLCDonleftside鈬�鈭�2d+5d3+13=鈭�4鈬�3d3+13=鈭�4鈬�d+13=鈭�4Subtract13fromboththesides鈬�d+13鈭�13=鈭�4鈭�13鈬�d=鈭�4鈭�13鈬�d=鈭�12鈭�13TakeLCDonrightside鈬�d=鈭�133

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Most popular questions from this chapter

In the following exercise, solve each equation using the Subtraction and Addition Properties of Equality.

x鈭�15=4

In the following exercise, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

23y=48

Solve: 鈭�4(q鈭�2)鈭�8=24.

Solve56=鈭�83r.

Translate and solve: The quotient of p and 鈭�9 is 81.
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