Q. 334 In the following exercise, solve... [FREE SOLUTION]

91影视

Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset 91影视 Explanations$ Math

2nd Edition 路 1240 pages

ISBN: 9780998625713

Chapter 2: Q. 334 (page 264)

In the following exercise, solve each equation with fraction coefficients.
$\frac{1}{3} b+ \frac{1}{5} = \frac{2}{5} b- \frac{3}{5}$

Short Answer

Expert verified

$Thesolutionforthegivenequaitonisb=12$

Step by step solution

Step 1. Given information

The given equation is $\frac{1}{3} b+ \frac{1}{5} = \frac{2}{5} b- \frac{3}{5}$

We have to solve the given equation.

Step 2. Explanation

$\begin{array}{l} 鈬� \frac{1}{3} b+ \frac{1}{5} = \frac{2}{5} b- \frac{3}{5} \\ 鈬� \frac{1}{3} b+ \frac{1}{5} = \frac{2}{5} b- \frac{3}{5} (FindtheLCDofallfractionsintheequation) \\ TheLCDis15 \\ 鈬� 15 脳 (\frac{1}{3} b+ \frac{1}{5})=15 脳 (\frac{2}{5} b- \frac{3}{5})(MultiplybothsidesbytheLCD) \\ 鈬� 15 脳 \frac{1}{3} b+ 15 脳 \frac{1}{5} =15 脳 \frac{2}{5} b- 15 脳 \frac{3}{5} (Distribute) \\ 鈬� 5 b+ 3 = 6 b- 9 (Simplify) \\ 鈬� 5 b-6b+ 3 = 6 b-6b- 9 (Subtract6bfrombothsides) \\ 鈬� 鈭� b+ 3 =- 9 (Simplify) \\ 鈬� 鈭� b+ 3 鈭� 3 =- 9 鈭� 3 (Subtract3frombothsides) \\ 鈬� 鈭� b=-12(Simplify) \\ 鈬� \frac{鈭� b}{鈭� 1} = \frac{-12}{鈭� 1} (Dividebothsideby-1) \\ 鈬� b=12(Simplify) \\ Thesolutionforthegivenequaitonisb=12 \end{array}$

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91影视

In the following exercise, solve each equation with fraction coefficients.
$\frac{1}{3} b+ \frac{1}{5} = \frac{2}{5} b- \frac{3}{5}$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Explanation

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91影视

In the following exercise, solve each equation with fraction coefficients.13b+15=25b-35

Short Answer

Step by step solution

Step 1. Given information

Step 2. Explanation

One App. One Place for Learning.

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In the following exercise, solve each equation with fraction coefficients.
$\frac{1}{3} b+ \frac{1}{5} = \frac{2}{5} b- \frac{3}{5}$