/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 2.90 Classify the equation as a condi... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 2: Q. 2.90 (page 250)

Classify the equation as a conditional equation, an identity, or a contradiction and then state the solution: 8(1-3x)+15(2x+7)=2(x+50)+4(x+3)+1

Short Answer

Expert verified

The solution is identity equation.

Step by step solution

01

Step 1. Given information

Equation:8(1-3x)+15(2x+7)=2(x+50)+4(x+3)+1

02

Step 2. Calculation

We have,

8(1-3x)+15(2x+7)=2(x+50)+4(x+3)+1鈬�8-24x+30x+105=2x+100+4x+12+1鈬�6x+113=6x+113鈬�6x-6x+113=6x-6x+113鈬�113=113

Therefore, the equation is identity.

The solution is all real numbers.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve:p鈭�41=鈭�73.

Solve4x=鈭�55.

Solve25n=14.

Solve: 鈭�6(r鈭�2)鈭�12=30.

In the following exercise, solve each equation using the Subtraction and Addition Properties of Equality.
x鈭�13=2
See all solutions

Recommended explanations on Math Textbooks

Mechanics Maths

Read Explanation

Calculus

Read Explanation

Decision Maths

Read Explanation

Theoretical and Mathematical Physics

Read Explanation

Logic and Functions

Read Explanation

Statistics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.