/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 561. In the following exercises, simp... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In the following exercises, simplify.

(a)10032

(b)49-52

(c)(-100)32

Short Answer

Expert verified

Part (a)10032=1000

Part (b)49-52=116807

Part (c)(-100)32=Not a real number

Step by step solution

01

Part (a) Step1. Given information 

The given expression is10032.

02

Part (a) Step2. Rewrite each expression as a radical first using the property,   amn=(an)m .

The power of the radical is the numerator of the exponent,3.

Since the denominator of the exponent is 2.

role="math" localid="1650718527378" 10032=(1002)3

03

Part (a) Step3.  Simplification 

(1002)3=(10)3=1000

04

Part (b) Step1. Given information 

The given expression is49-52.

05

Part (b) Step2. Rewrite using b-p=1bp 

49-52=1(49)52

06

Part (b) Step3. Change to radical form 

1(49)52=1(492)5

07

Part (b) Step4. Rewrite the radicand as a power 

1(492)5=1((7)22)5

08

Part (b) Step5. Simplification 

1((7)22)5=1(7)5=116807

09

Part (c) Step1. Given information 

The given expression is(-100)32.

10

Part (c) Step2. Rewrite in radical form 

(-100)32=(-1002)3

11

Part (c) Step3. Simplification 

There is no real number whose cube root is -100.

(-100)32

Not a real number.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.