Q. 8.8 Evaluate a2鈭抌28ab3聽for each v... [FREE SOLUTION]

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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset 91影视 Explanations$ Math

2nd Edition 路 1240 pages

ISBN: 9780998625713

Chapter 8: Q. 8.8 (page 909)

Evaluate $\frac{a^{2} 鈭� b^{2}}{8 a b^{3}}$ for each value:
$鈸� a = 1, b = 鈭� 1 鈸� a = \frac{1}{2}, b = 鈭� 1 鈸� a = 鈭� 2, b = 1$

Short Answer

Expert verified

$鈸� The value of \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} for a = 1, b = 鈭� 1 is 0 . 鈸� The value of \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} for a = \frac{1}{2}, b = 鈭� 1 is \frac{3}{16} . 鈸� The value of \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} for a = 鈭� 2, b = 1 is - \frac{3}{16} .$

Step by step solution

Step 1. Given Information

Evaluate $\frac{a^{2} 鈭� b^{2}}{8 a b^{3}}$ for each value:

$鈸� a = 1, b = 鈭� 1 鈸� a = \frac{1}{2}, b = 鈭� 1 鈸� a = 鈭� 2, b = 1$

Part (a) Step 1. Finding the value of a2−b28ab3 for a=1, b=−1

Putting $a = 1, b = 鈭� 1$ on the given expression

role="math" localid="1648381472744" $\frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{{(1)}^{2} 鈭� {(- 1)}^{2}}{8 路 1 路 {(- 1)}^{3}} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{1 鈭� 1}{8 路 1 路 (- 1)} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{0}{- 8} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = 0$

Part (b) Step 1. Finding the value of a2−b28ab3 for a=12 , b=−1

Putting $a = \frac{1}{2}, b = 鈭� 1$ on the given expression

$\frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{{(\frac{1}{2})}^{2} 鈭� {(- 1)}^{2}}{8 路 \frac{1}{2} 路 {(- 1)}^{3}} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{\frac{1}{4} 鈭� 1}{4 路 (- 1)} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{\frac{1}{4} 鈭� 1 路 \frac{4}{4}}{- 4} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{\frac{1}{4} 鈭� \frac{4}{4}}{- 4} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{\frac{1 - 4}{4}}{- 4} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{- 3}{4} 路 \frac{1}{- 4} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{3}{16}$

Part (c) Step 1. Finding the value of a2−b28ab3 for a=−2, b=1

Putting $a = 鈭� 2, b = 1$ on the given expression

role="math" localid="1648381736852" $\frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{{(- 2)}^{2} 鈭� {(1)}^{2}}{8 路 (- 2) 路 {(1)}^{3}} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{4 鈭� 1}{8 路 (- 2) 路 1} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = \frac{3}{- 16} \frac{a^{2} 鈭� b^{2}}{8 a b^{3}} = - \frac{3}{16}$

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91影视

Evaluate $\frac{a^{2} 鈭� b^{2}}{8 a b^{3}}$ for each value:
$鈸� a = 1, b = 鈭� 1 鈸� a = \frac{1}{2}, b = 鈭� 1 鈸� a = 鈭� 2, b = 1$

Short Answer

Step by step solution

Step 1. Given Information

Part (a) Step 1. Finding the value of a2−b28ab3 for a=1, b=−1

Part (b) Step 1. Finding the value of a2−b28ab3 for a=12 , b=−1

Part (c) Step 1. Finding the value of a2−b28ab3 for a=−2, b=1

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91影视

Evaluate a2鈭�b28ab3for each value:鈸�a=1,b=鈭�1鈸�a=12,b=鈭�1鈸�a=鈭�2,b=1

Short Answer

Step by step solution

Step 1. Given Information

Part (a) Step 1. Finding the value of a2−b28ab3 for a=1, b=−1

Part (b) Step 1. Finding the value of a2−b28ab3 for a=12 , b=−1

Part (c) Step 1. Finding the value of a2−b28ab3 for a=−2, b=1

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Most popular questions from this chapter

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Probability and Statistics

Logic and Functions

Geometry

Study anywhere. Anytime. Across all devices.

Evaluate $\frac{a^{2} 鈭� b^{2}}{8 a b^{3}}$ for each value:
$鈸� a = 1, b = 鈭� 1 鈸� a = \frac{1}{2}, b = 鈭� 1 鈸� a = 鈭� 2, b = 1$