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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset 91影视 Explanations$ Math

2nd Edition 路 1240 pages

ISBN: 9780998625713

Chapter 8: Q. 579 (page 1027)

In the following exercises, solve.
$\frac{1}{b - 2} + \frac{1}{b + 2} = \frac{3}{b^{2} - 4}$

Short Answer

Expert verified

The solution of the expression $\frac{1}{b - 2} + \frac{1}{b + 2} = \frac{3}{b^{2} - 4}$ is . $b = \frac{3}{2}$

Step by step solution

01

Step 1. Given Information.

An expression,

$\frac{1}{b - 2} + \frac{1}{b + 2} = \frac{3}{b^{2} - 4}$

02

Step 2. Find LCD

The LCD of the expression is $(b - 2) (b + 2)$

03

Step 3. Multiply both sides by LCD

$\frac{1}{b - 2} + \frac{1}{b + 2} = \frac{3}{b^{2} - 4} \frac{1}{b - 2} (b - 2) (b + 2) + \frac{1}{b + 2} (b - 2) (b + 2) = \frac{3}{b^{2} - 4} (b - 2) (b + 2) b + 2 + b - 2 = 3 2 b = 3 b = \frac{3}{2}$

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In the following exercises, use either method.

$\frac{\frac{3}{m} + \frac{3}{n}}{\frac{1}{m^{2}} 鈭� \frac{1}{n^{2}}}$

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