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Chapter 8: Q 234 (page 954)

Add2c2c+10+7cc2+9c+20.

Short Answer

Expert verified

The sum isc2+11(c+5)(c+4).

Step by step solution

01

Given Information  

The Given expression is2c2c+10+7cc2+9c+20.

02

Find the LCD of denominators.      

Factor the denominators.

2c+10=2(c+5)

c2+9c+20=(c+5)(c+4)

LCD=2(c+5)(c+4)

Rewrite the expression in factored form.

2c2(c+5)+7c(c+5)(c+4)

03

Rewrite each fraction as an equivalent fraction with the LCD.   

=2c(c+4)2(c+5)(c+4)+7c(2)2(c+5)(c+4)

=2c2+8c2(c+5)(c+4)+14c2(c+5)(c+4)

04

Add 

Take common denominator.

=2c2+8c+14c2(c+5)(c+4)

=2c2+22c2(c+5)(c+4)

Simplify numerator.

=2(c2+11)2(c+5)(c+4)

=c2+11(c+5)(c+4)

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