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Chapter 8: Q 202 (page 953)

Add4cd+3c+1d2-9.

Short Answer

Expert verified

The sum is4d-12+cc(d+3)(d-3).

Step by step solution

01

Given Information 

The Given expression is4cd+3c+1d2-9.

02

Find the LCD of denominators. 

Factor the denominators.

cd+3c=c(d+3)

d2-9=(d+3)(d-3)

LCD =c(d+3)(d-3)

Rewrite the expression.

=4c(d+3)+1(d+3)(d-3)

03

Rewrite each fraction as an equivalent fraction with the LCD. 

=4(d-3)c(d+3)(d-3)+1(c)c(d+3)(d-3)

Simplify numerator.

=4d-12c(d+3)(d-3)+cc(d+3)(d-3)

04

Add

Take common denominator.

=4d-12+cc(d+3)(d-3)

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