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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset 91影视 Explanations$ Math

2nd Edition 路 1240 pages

ISBN: 9780998625713

Chapter 10: Q 275 (page 1236)

Solve the quadratic equation by quadratic formula $6 a^{2} - 5 a + 2 = 0$

Short Answer

Expert verified

The required result is no real roots are possible .

Step by step solution

01

Given Information

The given equation is $6 a^{2} - 5 a + 2 = 0$

02

Write the quadratic equation in standard form and identify a,b,c

The quadratic equation is in standard form.

So,

$a = 6, b = - 5, c = 2$

03

Substitute the values in quadratic formula.

$x = \frac{- b 卤 \sqrt{b^{2} - 4 a c}}{2 a}$

$a = \frac{- (- 5) 卤 \sqrt{{(- 5)}^{2} - 4 (6) (2)}}{2 (6)} a = \frac{5 卤 \sqrt{25 - 48}}{12} a = \frac{5 卤 \sqrt{- 23}}{12}$

Roots of Negative number is not defined

Thus , no real roots are possible

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