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91Ó°ÊÓ

Solve the equation using quadratic formula.

2a2-6a+3=0

Short Answer

Expert verified

The roots area=3+32,a=3-32.

Step by step solution

01

 Given Information. 

The given equation is2a2-6a+3=0

02

Write the quadratic equation in standard form and identify a,b,c.

The quadratic equation is in standard form.

So,

a=2,b=-6,c=3.

03

Substitute the values in quadratic formula.  

a=-b±b2-4ac2aa=-(-6)±(-6)2-4(2)(3)2(2)a=6±36-244a=6±124

Use the square root property.

a=6±234

04

Rewrite to show two solutions.  

a1=6+234a1=3+32,a2=6-234a2=3-32

Thus, the solutions area=3-32,a=3+32.

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