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Chapter 3: Q. 33 (page 316)

In the following exercises, solve each number word

One number is 14less than another. If their sum is increased by seven, the result is 85. Find the numbers.

Short Answer

Expert verified

The number is 46and the other number is 32.

Step by step solution

01

Step 1. Given Information  

We are given that one number is 14less than another.

We have to find the numbers.

02

Step 2. Forming the equation   

Let the number be x,

So, the other number will be x-14,

We know that when sum of the numbers is incresed by 7, we get85

So, the equation will be,

x+(x-14)+7=85x+x-14+7=852x-7=85

03

Step 3. Solving the equation  

Adding 7on both sides, we get

2x-7=852x-7+7=85+72x=92

Dividing by 2,

x=922x=46

The other number will be 46-14=32,

Hence, the number is 46and the other number is32.

04

Step 4. Checking the solution   

Putting the value of xin the equation, we get

x+(x-14)+7=8546+(46-14)+7=8546+32+7=8585=85LHS=RHS

Hence the solution is correct.

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