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Chapter 3: Q. 275 (page 376)

A rectangular parking lot has perimeter 250 feet. The length is five feet more than twice the width. Find the length and width of the parking lot.

Short Answer

Expert verified

the length is 85feetand width is 40feet.

Step by step solution

01

Step 1. Given information

A rectangular parking lot has perimeter P=250feet

The length is five feet more than twice the width.

02

Step 2. Finding length and width of a rectangle

Let P be the perimeter,x be the width and 2x+5 be the length of rectangle ABCD

Now substitute the given values in the formula for perimeter P=2L+2W

P=2(2x+5)+2x250=2(2x+5)+2x250=4x+10+2x250=6x+10250-10=6x240=6x2406=6x6x=2406x=402x+5=(2脳40)+5=80+5=85

So,the length is 85feetand width is40feet

03

Step 3. Checking

Check the solution by using the formula P=2L+2W

250=2(85)+2(40)250=170+80250=250[true]

Therefore,the length is85feet and width is 40feet

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