91影视

We have been given a graph.

We have to write the inequality shown by the graph.

The line $y=-\frac{1}{3}x-2$is the boundary line.

On one side of the line are the points with $y>-\frac{1}{3}x-2$and on the other side of the line are the points with $y<-\frac{1}{3}x-2$.

Let鈥檚 test the point (0, 0) and see which inequality describes its side of the boundary line.

At (0, 0) , which inequality is true:

$$\begin{gathered} y>-\frac{1}{3}x-2 \\ 0\stackrel{?}{>}-\frac{1}{3}\left(0\right)-2 \\ 0>-2 \end{gathered}$$ or role="math" localid="1647603941253" $$\begin{gathered} y<-\frac{1}{3}x-2 \\ 0\stackrel{?}{<}-\frac{1}{3}\left(0\right)-2 \\ 0鈮�-2 \end{gathered}$$

So the side with (0, 0) is the side where $y<-\frac{1}{3}x-2$.

We need to find the inequality for the region that does not contain (0,0).

Since the boundary line is graphed as a solid line, the inequality includes an equal sign.

The graph shows the solution to the inequality $y鈮�-\frac{1}{3}x-2$.