/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 504 Determine whether each ordered p... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine whether each ordered pair is a solution to the inequality y>x-1.

(a) (0,1)

(b) (-4,-1)

(c) (4,2)

(d) (3,0)

(e) (-2,-3)

Short Answer

Expert verified

(a) and (b) satisfy the inequality.

Step by step solution

01

Step 1. Given information 

We have been given an inequality y>x-1.

We have to check whether each ordered pair is a solution to this inequality.

02

Part (a) Step 1. Substitute (0,1) in the given inequality.

y>x-11>?0-11>-1

Since the inequality is satisfied, this ordered pair is a solution to the inequality.

03

Part (b) Step 1. Substitute (-4,-1) in the given inequality.

y>x-1-1>?-4-1-1>-5

Since the inequality is satisfied, this ordered pair is a solution to the inequality.

04

Part (c) Step 1. Substitute (4,2) in the given inequality.

2>4-12>?4-12≯3

Since the inequality is not satisfied, this ordered pair is not a solution to the inequality.

05

Part (d) Step 1. Substitute (3,0) in the given inequality.

y>x-10>?3-10≯2

Since the inequality is not satisfied, this ordered pair is not a solution to the inequality.

06

Part (e) Step 1. Substitute (-2,-3) in the given inequality.

y>x-1-3>?-2-1-3≯-3

Since the inequality is not satisfied, this ordered pair is not a solution to the inequality.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.