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Chapter 4: Q. 498 (page 540)

In the following exercises, find the equation of each line. Write the equation in slope鈥搃ntercept form.

Perpendicular to the line x-2y=5, Containing the point role="math" localid="1647510827042" -2,2.

Short Answer

Expert verified

The equation of the line is y=-2x-2.

Step by step solution

01

Step 1. Given Information  

We are given a line with equation x-2y=5the point -2,2.

We have to find the slope-intercept form of the line containing the points.

02

Step 2. Finding the slope  

Writing the given equation in slope intercept form, we get

x-2y=5-2y=-x+5y=12x-52

The slope is m=12,

The slope of the perpendicular lines is negative reciprocals so

m'=-112m'=-2

03

Step 3. Finding the slope-intercept form of the line 

The slope-intercept form of the line is given by,

y-y1=mx-x1y-2=-2(x+2)y-2=-2x-4y=-2x-4+2y=-2x-2

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Find an equation of a line with slope25and y-intercept(0,4).

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