91影视

The given quadrant are (a)$(3,-1)$(b)$(-3,1)$(c)$(-2,2)$(d)$(-4,-3)$(e)$(1,\frac{14}{5})$

(a)Since $x=3$, the point is to the right of the $y-$axis. Since $y=-1$, the point is below the $x-$axis. The point $(3,-1)$is in Quadrant lV.

(b) Since $x=-3$,the point is to the left of the $y-$axis. Also, since $y=1$, the point is above the $x-$axis. The point is $(-3,1)$in Quadrant II.

(c) Since $x=-2$,the point is to the left of the $y-$axis. Also, since $y=2$, the point is above the $x-$axis. The point is $(-2,2)$in Quadrant II.

(d)Since $x=-4$, the point is to the left of the $y-$axis. Also, since $y=-3$, the point is below the $x-$axis. The point $(-4,-3)$is in Quadrant III.

(e)Since $x=1$, the point is to the right of the $y-$axis. Since $y=\frac{14}{5}$, the point is above the $x-$axis. It can be seen that the point $(1,\frac{14}{5})$is in Quadrant I.

The quadrant that each point is placed using a rectangular coordinate system