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Chapter 4: Q. 132 (page 534)

Find an equation of a line perpendicular to the line y=12x-3that contains the point (6,4).

Short Answer

Expert verified

The equation of the line isy=-2x+16.

Step by step solution

01

Step 1. Given Information.

Equation of the line, y=12x-3

Point,(6,4)

02

Step 2. Finding the slope

The slope-intercept form is,

y=mx+b

Comparing the equation of the line y=12x-3,

m1=12.

When two lines are perpendicular to each other,

m1脳m2=-1鈬�12脳m2=-1鈬�m2=-2

03

Step 3. Equation of the line.

The point-slope form is,

(y-y1)=m(x-x1)

Inputting the values,

(y-4)=-2(x-6)y-4=-2x+12y=-2x+16

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