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Chapter 4: Q. 130 (page 532)

Find an equation of a line parallel to the line y=12x-3that contains the point (6,4).

Short Answer

Expert verified

The equation of the line isy=12x+1.

Step by step solution

01

Step 1. Given Information.

Equation of the line, y=12x-3.

Point is(6,4).

02

Step 2. Finding the slope.

The slope-intercept form is,

y=mx+b

Comparing the equation y=12x-3we get,

m1=12

The slope of the parallel lines is equal.

m1=m2鈬�m2=12

03

Step 3. Equation of the line.

The point-slope form is,

(y-y1)=m(x-x1)

Inputting the value,

(y-4)=12(x-6)y-4=12x-3y=12x+1

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