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Factor:6g2+19g-20

Short Answer

Expert verified

The factorization of6g2+19g-20is(g+4)(6g-5)

Step by step solution

01

Step 1. Given information

Given expression is6g2+19g-20

02

Step 2. Find the product of a×c

a×c=6×(-20)=-120

03

Step 3. Find the last terms of the binomials.

Find the numbers that multiply to -120and add to 19

Factors of -120Sum of factors
24, -524 + (-5) = 19
04

Step 4. Factorization

Use 24and -5as the last terms of the binomials.

6g2+4g-5g-20=6g(g+4)-5(g+4)=(g+4)(6g-5)

05

Step 5. Check

(g+4)(6g-5)=6g2+24g-5g-20=6g2+19g-20

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