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Factor:h2+4h-12

Short Answer

Expert verified

The factorization of h2+4h-12is,(h-2)(h-6).

Step by step solution

01

Step 1. Given information

Given expression ish2+4h-12.

02

Step 2. Find the last terms of the binomials

Write the factors as two binomials with the first terms h.

(h)(h)

Find two numbers that multiply to -12and add to 4.

Factors of -12Sum of factors
1, -121 + (-12) = -11
2, -62+ (-6) = -4
3, -43 + (-4) = -1
-1, 12-1 + 12 = 11
-2, 6-2 + 6 = 4*
-3, 4-3 + 4 = 1
03

Step 3. Factorization

Use -2and 6 as the last terms of the binomials.

h2-4h+12=(h-2)(h+6)

04

Step 4. Check

(h-2)(h+6)=h2-2h+6h-12=h2+4h-12

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