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Factor completely:

5u2-15u-270

Short Answer

Expert verified

The factored form is 5(u-9)(u+6).

Step by step solution

01

Step 1. Given Information  

We are given a polynomial 5u2-15u-270,

We have to factor the given polynomial.

02

Step 2. Factoring the polynomial  

Factoring out GCF 5, we get

5u2-15u-270=5u2-3u-54=5u2-9u+6u-54=5(u(u-9)+6(u-9))

Factoring out GCF u-9, we get

5u2-15u-270=5(u-9)(u+6)

03

Step 3. Checking the factors  

Mutiplying the factors, we get

5(u-9)(u+6)=5u2-15u-2705(u(u-9)+6(u-9))=5u2-15u-2705u2-9u+6u-54=5u2-15u-2705u2-3u-54=5u2-15u-2705u2-15u-270=5u2-15u-270LHS=RHS

Hence, the factors are correct.

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