Q. 101 In the following exercises, fact... [FREE SOLUTION]

91影视

Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset 91影视 Explanations$ Math

2nd Edition 路 1240 pages

ISBN: 9780998625713

Chapter 7: Q. 101 (page 832)

In the following exercises, factor each trinomial of the form $x^{2} + b x y + c y^{2}$
$m^{2} - 12 m n + 20 n^{2}$

Short Answer

Expert verified

The factorization of $m^{2} - 12 m n + 20 n^{2}$ is $(m - 2 n) (m - 10 n)$

Step by step solution

Step 1. Given information

Given expression is $m^{2} - 12 m n + 20 n^{2}$

Step 2. Find the last terms of the trinomials.

The factors of the expression:

The factors of 20	Sum of factors
5, 4	5 + 4 = 9
10, 2	10 + 2 = 12
-5, -4	-5 + (-4) = -9
-10, -2	-10 + (-2) = -12

Step 3. Factorization

Use $- 2$ and $- 10$ as the last terms of the trinomials.

$m^{2} - 12 m n + 20 n^{2} = (m - 2 n) (m - 10 n)$

Step 4. Check

$(m - 2 n) (m - 10 n) = m^{2} - 2 m n - 10 m n + 20 n^{2} = m^{2} - 12 m n + 20 n^{2}$

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91影视

In the following exercises, factor each trinomial of the form $x^{2} + b x y + c y^{2}$
$m^{2} - 12 m n + 20 n^{2}$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find the last terms of the trinomials.

Step 3. Factorization

Step 4. Check

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91影视

In the following exercises, factor each trinomial of the form x2+bxy+cy2m2-12mn+20n2

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find the last terms of the trinomials.

Step 3. Factorization

Step 4. Check

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Applied Mathematics

Mechanics Maths

Theoretical and Mathematical Physics

Geometry

Discrete Mathematics

Calculus

Study anywhere. Anytime. Across all devices.

In the following exercises, factor each trinomial of the form $x^{2} + b x y + c y^{2}$
$m^{2} - 12 m n + 20 n^{2}$