Chapter 8: Problem 3
Solve for \(x: 3 x^{2}+8 x+2=0\).
Short Answer
Expert verified
The solutions are \( x = \frac{-4 + \sqrt{10}}{3} \) and \( x = \frac{-4 - \sqrt{10}}{3} \).
Step by step solution
01
Identify the coefficients
We have the quadratic equation in the form of \( ax^2 + bx + c = 0 \). Here, \( a = 3 \), \( b = 8 \), and \( c = 2 \).
02
Use the quadratic formula
The quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). We will use this formula to solve for the roots of the equation.
03
Calculate the discriminant
The discriminant \( \Delta \) is given by \( b^2 - 4ac \). Substituting the values, \( \Delta = 8^2 - 4 \times 3 \times 2 = 64 - 24 = 40 \).
04
Substitute into the quadratic formula
We substitute into the quadratic formula: \[ x = \frac{-8 \pm \sqrt{40}}{6} \].
05
Simplify the expression
First, calculate \( \sqrt{40} = \sqrt{4 \times 10} = 2 \sqrt{10} \). Substituting this into the formula gives: \[ x = \frac{-8 \pm 2\sqrt{10}}{6} \].
06
Simplify further
We can simplify the expression by dividing each term by 2: \[ x = \frac{-4 \pm \sqrt{10}}{3} \].
07
Conclusion: Solutions for x
The solutions to the quadratic equation are \( x = \frac{-4 + \sqrt{10}}{3} \) and \( x = \frac{-4 - \sqrt{10}}{3} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool used to find the solutions of quadratic equations. A quadratic equation is any equation of the form \( ax^2 + bx + c = 0 \). The quadratic formula is expressed as:
By using the quadratic formula, you can find the two possible values for \( x \) by computing \( -b + \sqrt{b^2 - 4ac} \) and \( -b - \sqrt{b^2 - 4ac} \). Each solution provides a point where the parabola represented by the quadratic equation touches or crosses the x-axis.
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
By using the quadratic formula, you can find the two possible values for \( x \) by computing \( -b + \sqrt{b^2 - 4ac} \) and \( -b - \sqrt{b^2 - 4ac} \). Each solution provides a point where the parabola represented by the quadratic equation touches or crosses the x-axis.
Discriminant
The discriminant is a key component of the quadratic formula, represented by \( \Delta = b^2 - 4ac \). It provides valuable information about the nature of the roots of the quadratic equation:
- If \( \Delta > 0 \), the equation has two distinct real roots.
- If \( \Delta = 0 \), the equation has exactly one real root, meaning the parabola touches the x-axis at one point.
- If \( \Delta < 0 \), the quadratic equation has two complex roots, meaning the parabola does not touch the x-axis.
Roots of Equations
The roots of a quadratic equation refer to the values of \( x \) that satisfy the equation. In other words, they are the solutions where the equation equals zero. Roots can be found using various methods, including:
- Factoring - expressing the quadratic as a product of two binomials.
- Completing the square - rewriting the equation in a form that reveals the roots.
- Using the quadratic formula - a universal method applicable to all quadratic equations.
- \( x = \frac{-4 + \sqrt{10}}{3} \)
- \( x = \frac{-4 - \sqrt{10}}{3} \)