Chapter 9: Problem 84
Solve using the quadratic formula. $$ -2(y-4)(y+1)=3 y+10 $$
Short Answer
Expert verified
No real solutions exist as the discriminant is negative.
Step by step solution
01
Expand the Equation
First, expand the left side of the equation: \(-2(y-4)(y+1)\). Use the distributive property (FOIL method) to get:\[-2(y^2 + y - 4y - 4) = -2(y^2 - 3y - 4)\].Simplify it to get:\[-2y^2 + 6y + 8\].So the equation becomes:\(-2y^2 + 6y + 8 = 3y + 10\).
02
Rearrange the Equation
Rearrange the equation to standard quadratic form (\(ax^2 + bx + c = 0\)):\(-2y^2 + 6y + 8 - 3y - 10 = 0\),which simplifies to:\(-2y^2 + 3y - 2 = 0\).
03
Identify Coefficients
Identify the coefficients from the equation \(-2y^2 + 3y - 2 = 0\):- \(a = -2\)- \(b = 3\)- \(c = -2\).
04
Apply the Quadratic Formula
Use the quadratic formula: \(y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).Substitute the values:\[y = \frac{-3 \pm \sqrt{3^2 - 4(-2)(-2)}}{2(-2)}\].Calculate the discriminant:\[b^2 - 4ac = 3^2 - 4 \cdot (-2) \cdot (-2) = 9 - 16 = -7\].Since the discriminant is negative, this indicates that there are no real solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Distributive Property
The distributive property is a key tool in algebra when dealing with expressions inside parentheses. It allows you to multiply a term by all elements inside the parenthesis. This property is often expressed as \( a(b + c) = ab + ac \). In our original problem, you observe this property in action when expanding \(-2(y-4)(y+1)\). We use the distributive property—a process often referred to as the FOIL method when applied to binomials—to expand this expression fully. The steps include:
- Multiplying the first terms: \( y \times y = y^2 \).
- Multiplying the outer terms: \( y \times 1 = y \).
- Multiplying the inner terms: \(-4 \times y = -4y \).
- Multiplying the last terms: \(-4 \times 1 = -4 \).
Quadratic Equation
A quadratic equation is a type of polynomial equation of the form \( ax^2 + bx + c = 0 \), where \( a, b, \) and \( c \) are constants. In our example, we rearranged the given equation to match this standard format. The given equation \(-2y^2 + 6y + 8 = 3y + 10 \) is first simplified and rearranged to \(-2y^2 + 3y - 2 = 0 \). The quadratic equation mainly involves:
- Identifying the coefficients: the \( a \) term represents the coefficient of \( y^2 \), \( b \) is the coefficient of \( y \), and \( c \) is the constant term.
- Locating these coefficients is critical for solving the equation using the quadratic formula or other methods.
Discriminant
The discriminant helps determine the nature of the solutions in a quadratic equation, calculated by the expression \( b^2 - 4ac \). It reveals crucial information about the roots without requiring you to find them explicitly. Here’s how the discriminant is used:
- If \( b^2 - 4ac > 0 \), the equation has two distinct real roots.
- If \( b^2 - 4ac = 0 \), there is exactly one real root, also known as a repeated root.
- If \( b^2 - 4ac < 0 \), there are no real roots, but two complex roots.