Chapter 3: Problem 35
Find the intercepts and graph them. $$ 15 x+4 y=-60 $$
Short Answer
Expert verified
X-intercept: (-4, 0); Y-intercept: (0, -15).
Step by step solution
01
Identify the Problem
We need to find the intercepts of the equation \(15x + 4y = -60\). These are the points where the line crosses the x-axis and y-axis.
02
Find the X-intercept
To find the x-intercept, set \(y = 0\) in the equation and solve for \(x\).\\[15x + 4(0) = -60\] This simplifies to:\[15x = -60\]Divide both sides by 15:\[x = -4\]Thus, the x-intercept is \((-4, 0)\).
03
Find the Y-intercept
To find the y-intercept, set \(x = 0\) and solve for \(y\). \\[15(0) + 4y = -60\]This simplifies to:\[4y = -60\]Divide both sides by 4:\[y = -15\]Thus, the y-intercept is \((0, -15)\).
04
Plot the Intercepts on a Graph
Using the intercepts found, plot \((-4, 0)\) and \((0, -15)\) on the coordinate plane. These points represent where the line crosses the axes.
05
Draw the Line
Draw a straight line passing through the points \((-4, 0)\) and \((0, -15)\). This line represents the graph of the equation \(15x + 4y = -60\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the X-intercept
The x-intercept is a fundamental concept in graphing and understanding linear equations. To locate the x-intercept of a given linear equation, you set the value of the dependent variable, or the output variable—which is usually "y"—to zero. In simpler terms, the x-intercept is the location where the graph of the equation crosses, or touches, the x-axis without going above or below the axis. This point will always be in the form
- \((x, 0)\)
- \((-4, 0)\).
- \(-4\), marking the intersection with the x-axis.
- a graph of the line on a coordinate plane.
Understanding the Y-intercept
The y-intercept of a linear equation is the point where the line crosses the y-axis. Similar to finding the x-intercept, the y-intercept is found by setting \(x = 0\). This point is crucial in understanding how a linear equation behaves and looks on a graph. The y-intercept is expressed in a coordinate form as
- \((0, y)\)
- \((0, -15)\).
Graphing Linear Equations
Graphing linear equations is the process of visually representing the solution set of an equation on a coordinate plane. When we say we want to graph the equation \(15x+4y=-60\), we're looking to draw a straight line. To correctly graph this linear equation:
Identify both the x-intercept and y-intercept, which in this problem are \((-4, 0)\) and \((0, -15)\) respectively.
Identify both the x-intercept and y-intercept, which in this problem are \((-4, 0)\) and \((0, -15)\) respectively.
- Use these intercepts as reference points.
- Plot both points on the coordinate plane.
- Draw a straight line that passes through both plotted intercepts.
Navigating the Coordinate Plane
The coordinate plane is a two-dimensional surface defined by a horizontal line (x-axis) and a vertical line (y-axis), which intersect at a point called the origin
- \((0, 0)\).
- \((x, y)\).
- First Quadrant: Both \(x\) and \(y\) are positive.
- Second Quadrant: \(x\) is negative, \(y\) is positive.
- Third Quadrant: Both \(x\) and \(y\) are negative.
- Fourth Quadrant: \(x\) is positive, \(y\) is negative.